A quadrilateral is a kite if the diagonals are:
i) perpendicular
ii) bisect each other
iii) not equal ( together with conditions i and ii this would make the quadrilateral a square)
Another definition of the kite is :
a quadrilateral with 2 pairs of equal adjacent sides.
Let's check the choices one by one:
A. <span>∠M is a right angle and MK bisects ∠LMJ.
according to these, ML and MJ may well be not equal...
</span><span>B. LM = JM = 3 and JK = LK = √17.
</span>
this makes the quadrilateral a kite.
<span>C. MK intersects LJ at its midpoint
</span>
if they are not perpendicular, the quadrilateral is not a kite.
<span>D. The slope of MK is –1 and the slope of LJ is 1.
this only means that MK and LJ are perpendicular, but not whether they bisect each other,
Answer: only B</span>
Answer:
139 ( D )
Step-by-step explanation:
Interest rate on loan = 4% = 0.04
Number of payments = 15
First 10 payments = 100 each
last 5 payments = 200 each
Calculating the value of K
K = [ ( 100 / 0.04 * ( 1-1 / 1.04^10 ) + 200/0.04 * ( 1-1 / (1 +0.04)^5)* 1 /1.04^10)
* 1.1 - 100 / 0.04 * ( 1-1 / (1+0.04)^5 ) - 200/0.04 * (1-1 /1.04^5) * 1/1.04^10)*0.04 / ( 1-1 / 1.04^5) * (1 + 0.04)^5
= 138.6051 ≈ 139
Answer:
Step-by-step explanation:
the question is asking for the length of the side labeled x
use Pythagoras' theorem to find that side
where c = x because c represents the hypotenuse in the theorem and x is on the hypotenuse in this problem
c = 
sooo plug in a = 14 and b = 10
c = 
c = 
c = 
c= 17.20465..... ( that's the approx. length of side x in the problem )
since this is a right triangle we could use trigonometry to find the two angles use SOH CAH TOA to remember how those functions fit on the triangle.
Sin(Ф)=Opp/Hyp Cos(Ф)=Adj/Hyp Tan(Ф)=Opp/Adj
since we know the Hyp (hypotenuse) and the side adjacent will be the side with the 10 soooo...
Cos(Ф)=10/17.20465
Ф = arcCos(10/17.20465)
Ф = 54.4623° is the angle on the side with 10
the side with 14 then has an angle of 35.5376°
:)
Answer:
the slope of the line is <u>4</u><u> </u><u>and</u><u> </u><u>the</u><u> </u><u>working</u><u> </u><u>is</u><u> </u>in the attached picture
