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Vanyuwa [196]
2 years ago
12

PLS HELP WILL MARK AS BRAINLIST

Mathematics
2 answers:
kykrilka [37]2 years ago
5 0

Answer:

Step-by-step explanation:

x = -6 ± 3√2

x = -6 + 3√2

x = -6 - 3√2

babunello [35]2 years ago
5 0

Step-by-step explanation:

\sf  x=-6  \:  \pm 3\sqrt{2}

\sf \: x=-6 \: +  3 \sqrt{2}

\sf \: x=-6 \: - 3 \sqrt{2}

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erastova [34]

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2 years ago
for a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height,
kolbaska11 [484]

Problem

For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground

Solution

We know that the x coordinate of a quadratic function is given by:

Vx= -b/2a

And the y coordinate correspond to the maximum value of y.

Then the best options are C and D but the best option is:

D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a

The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.​

7 0
8 months ago
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olga_2 [115]
C is the answer.
The other ones do not make as much sense i am not completely sure.
8 0
3 years ago
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pav-90 [236]

Answer:                                                                                                                       3m

And I had to write something for this to be ong enough so thats what this is:)

3 0
2 years ago
What is the m2ABC?<br> a) m ABC = 15°<br> b) m2ABC = 45°<br> c) MLABC = 60°<br> d) MZABC = 75°
WITCHER [35]

Answer:

m∠ABC = 60°

Step-by-step explanation:

4 0
3 years ago
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