Answer:
D. 5 +6k/n
Step-by-step explanation:
The width of the interval is (5 -2) = 3. The width of one of n parts of it will be ...
3/n
Then the difference between the left end point of the interval and the value of x at the right end of the k-th rectangle will be ...
k·(3/n) = 3k/n
So, the value of x at that point is that difference added to the interval's left end:
2 + 3k/n
The value of the function for this value of x is ...
f(2 +3k/n) = 2(2 +3k/n) +1 = (4 +6k/n) +1
= 5 +6k/n
Answer:
The answer is 4 + 3/6 + 2/6
Step-by-step explanation:
i. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the
Answer:
<h3>The diameter is 4cm</h3>
Step-by-step explanation:
Volume of a sphere is
Where r is the radius
diameter = radius × 2
To find the diameter we must first find the radius
Volume = 34cm³
That's
![34 = \frac{4}{3} \pi {r}^{3} \\ \\ 34 \times 3 = 4\pi {r}^{3} \\ \\ 102 = 4\pi {r}^{3} \\ {r}^{3} = \frac{102}{4} \pi \\ \\ r = \sqrt[3]{ \frac{51}{2\pi}} \\ \\ r = 2.01 \\ \\ r = 2.0 cm](https://tex.z-dn.net/?f=34%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20%7Br%7D%5E%7B3%7D%20%20%5C%5C%20%20%5C%5C%2034%20%5Ctimes%203%20%3D%204%5Cpi%20%7Br%7D%5E%7B3%7D%20%20%5C%5C%20%20%5C%5C%20102%20%3D%204%5Cpi%20%7Br%7D%5E%7B3%7D%20%20%5C%5C%20%20%7Br%7D%5E%7B3%7D%20%20%20%3D%20%5Cfrac%7B102%7D%7B4%7D%20%5Cpi%20%5C%5C%20%20%5C%5C%20r%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B51%7D%7B2%5Cpi%7D%7D%20%20%5C%5C%20%20%5C%5C%20r%20%3D%202.01%20%5C%5C%20%20%5C%5C%20r%20%3D%202.0%20cm)
Diameter = 2 × 2cm
<h3>= 4cm</h3>
Hope this helps you
I don’t why it kinda blurry for me.
