Answer:
1 and 11/20
Step-by-step explanation:
3/4 + 4/5
= 15/20 + 16/20
= 31/20
= 1 and 11/20
Hope this helped!
Answer:
387.4
Step-by-step explanation:
Have a nice day
161 - 49 = 128
128 / 2 = 64
64 + 64 +49 =161
first number is 64
second is 113
Answer:
x<48.83778966 :) have a great day!
Step-by-step explanation:
Answer:
![V = \frac{1}{3} (\pi \cdot 10^2 \cdot 16) \\\\V = \frac{1}{3} (1600 \pi ) \\\\V = 1675.52 \: m^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%28%5Cpi%20%5Ccdot%2010%5E2%20%5Ccdot%2016%29%20%5C%5C%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%281600%20%5Cpi%20%29%20%5C%5C%5C%5CV%20%3D%201675.52%20%5C%3A%20m%5E3)
The maximum amount of sand that can be stored in this structure is 1675.52 m³.
Step-by-step explanation:
The volume of a conical-shaped structure is given by
![V = \frac{1}{3} (\pi \cdot r^2 \cdot h)](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%28%5Cpi%20%5Ccdot%20r%5E2%20%5Ccdot%20h%29)
Where r is the radius and h is the height of the structure.
We are given that
radius = 10m
height = 16m
Substituting the above values into the formula, we get
![V = \frac{1}{3} (\pi \cdot 10^2 \cdot 16) \\\\V = \frac{1}{3} (1600 \pi ) \\\\V = 1675.52 \: m^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%28%5Cpi%20%5Ccdot%2010%5E2%20%5Ccdot%2016%29%20%5C%5C%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%281600%20%5Cpi%20%29%20%5C%5C%5C%5CV%20%3D%201675.52%20%5C%3A%20m%5E3)
Therefore, the maximum amount of sand th can be stored in this structure is 1675.52 m³.