Answer:

Step-by-step explanation:

<u>Apply exponent rule : </u>
<u>Add 11 +2 = 13</u>
- <u />

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<u>OAmalOHopeO</u>
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Answer:
Just one of the ones in the numerator and the one in the denominator
Step-by-step explanation:
Answer: B 10 Times large
Step-by-step explanation:The first 5 is 500,000 And the second 5 is 50,000
500,000÷ 50,000= 10
Step-by-step explanation:
it's something in algebra i don't remember but basically the top number (12) has the x on the bottom which is multiplication and the bottom number (8) has addition so those tell u how ur supposed to get those numbers
so basically u need to find two numbers that add up to 8 and multiply to 12 so the factors are 6 and 2 because 6 • 2 is 12 and 6 + 2 = 8. hope this helps
Answer:

Step-by-step explanation:
The given expression is

First, we need to factor each denominator

So, the least common factor (LCF) is
, because they are the factors that repeats.
Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

Therefore, the expression is equivalent to
