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raketka [301]
2 years ago
10

Choose the equation of a line with a slope m = -2/3 and a point (3, 3) on the line.

Mathematics
1 answer:
xeze [42]2 years ago
4 0

Answer:

last option: y = (-2/3)x + 5

Step-by-step explanation:

slope-intercept equation:  y = mx + b

where m is the slope and b is the y-intercept

if slope m = -2/3, then  y = (-2/3)x + b

if point (3, 3) is on the line, substitute x=3 and y=3 into the equation and solve for b:

3 = (-2/3)3 + b

⇒ 3 = -2 + b

⇒ b = 5

Therefore, equation:  y = (-2/3)x + 5

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Answer:  48\sqrt{7}

Step-by-step explanation:

Given expression, \sqrt{32} \times \sqrt{28}\times \sqrt{3}\times \sqrt{6}

= √(4×8)×√(4×7)×√3×√(3×√2)

= √4×√8×√4×√7×√3×√3×√2 ( because √(m×n)=√m×√n)

=√4×√4×√8×√2×√7×√3×√3

=4×√(4×2)×√2×√7×3

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Thus,\sqrt{32} \times \sqrt{28}\times \sqrt{3}\times \sqrt{6}=48\sqrt{7}


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4 years ago
Ali and Janet are selling gifts at a local craft show. For every bar of soap that Ali sells, she earns $5. For every mug that Ja
Alexus [3.1K]

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