Answer:
Continuously
Step-by-step explanation:
Compounded continuously:
A = Pe^(rt)
A = 11,000 e^(0.0625 × 10)
A = 20,550.71
Compounded semiannually (twice per year):
A = P(1 + r)^t
A = 11,000 (1 + 0.063/2)^(2×10)
A = 11,000 (1 + 0.0315)^20
A = 20,453.96
Answer: 47 and 16
Step-by-step explanation:
- Make Two Equations
x + y = 63
x - y = 31
- Set one of the equations equal to one of the variables
x + y = 63
x = 31 + y
- Substitute the equation back into the other one
(31 + y) + y = 63
31 + 2y = 63
2y = 32
y = 16
- Substitute the answer back into the equation
x + y = 63
x + 16 = 63
x = 47
I think the answer is 10, 20, and 4
A standard deck of cards has 52 cards. Half of the deck has red cards and half has black cards. So the first probability would be 26/52, or 1/2 (simplified, it's half the deck).
Then you put the card back and choose a 3. There are 4 cards with the number 3 in the deck. So it's 4/52.
Then you multiply both the probabilities
26/52 x 4/52 =

= 1/26
E=3x6x6
e=3x36
e=108
hope it helps