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enyata [817]
2 years ago
7

I’m not sure how to solve this.

Mathematics
1 answer:
Anarel [89]2 years ago
4 0

Answer:  2x + h - 2

===============================================

Work Shown:

Part 1

f(x) = x^2 - 2x + 8\\\\f(x+h) = (x+h)^2 - 2(x+h) + 8\\\\f(x+h) = (x+h)(x+h) - 2(x+h) + 8\\\\f(x+h) = x(x+h)+h(x+h) - 2(x+h) + 8\\\\f(x+h) = x^2+xh+xh+h^2 - 2x-2h + 8\\\\f(x+h) = x^2+2xh+h^2 - 2x-2h + 8\\\\

Part 2

\frac{f(x+h)-f(x)}{h} = \frac{(x^2+2xh+h^2 - 2x-2h + 8) - (x^2-2x+8)}{h}\\\\\frac{f(x+h)-f(x)}{h} = \frac{x^2+2xh+h^2 - 2x-2h + 8 - x^2+2x-8}{h}\\\\\frac{f(x+h)-f(x)}{h} = \frac{2xh+h^2-2h}{h}\\\\\frac{f(x+h)-f(x)}{h} = \frac{h(2x+h-2)}{h}\\\\\frac{f(x+h)-f(x)}{h} =2x+h-2\\\\

-------------

In part 1, I replaced every x with x+h. Then I expanded things out using the distributive property. This is to figure out what f(x+h) is equal to.

In part 2, I then computed the difference quotient. Notice how basically all of the terms in the original f(x) cancel out. Leaving nothing but h terms behind. We factor out h to cancel it with the denominator.

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A club had some money to purchase new chairs. After buying 355 chairs at $199 each, there was $1,068 remaining. How much money d
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Answer:

<h2><u><em>$71,713</em></u></h2>

Explanation:

  • Find The Total Cost Of The 355 Chairs
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355 · 199 = $70,645

  • Club Spent $70,645 And Had $1,068 Remaining

$70,645 + $1,068 = $71,713

<h2><em><u>The Club Had $71,713 At First</u></em></h2>

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3 years ago
Penelope determined the solutions of the quadratic function by completing the square. F(x) = 4x2 8x 1 –1 = 4x2 8x –1 = 4(x2 2x)
Ymorist [56]

By solving the quadratic equation using completing the square method we got that Penelope should have added 4 to both sides instead of adding 1.

<h3>What is quadratic equation ?</h3>

Any equation of the form ax^2+bx+c=0 where x is variable and a, b, and c are any real numbers where a ≠ 0 is called quadratic equation .

Given work of Penelope is

$$\begin{aligned}&f(x)=4 x^{2}+8 x+1 \\&-1=4 x^{2}+8 x \\&-1=4\left(x^{2}+2 x\right) \\&-1+1=4\left(x^{2}+2 x+1\right) \\&0=4(x+2)^{2} \\&0=(x+2)^{2} \\&0=x+2 \\&-2=x\end{aligned}$$

Now we can see that Penelope determined the solutions of the quadratic function by completing the square. so he must have been done as following

$$\begin{aligned}&f(x)=4 x^{2}+8 x+1 \\&-1=4 x^{2}+8 x \\&-1=4\left(x^{2}+2 x\right) \\&-1+4=4\left(x^{2}+2 x+1\right) \\&3=4(x+2)^{2} \\&\frac{3}{4} =x+2)^{2} \\&\frac{\pm\sqrt3}{2} =x+2 \\&\frac{-2\pm\sqrt3}{2} =x\end{aligned}$$

By solving the quadratic equation using completing the square method we got that Penelope should have added 4 to both sides instead of adding 1.

To learn more about quadratic equations visit : brainly.com/question/1214333

8 0
2 years ago
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