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Gnesinka [82]
3 years ago
8

Can someone help me f(x) = - 7(x - 11)3(x + 13)3(x + 2)(x - 3)5

Mathematics
1 answer:
jekas [21]3 years ago
6 0

Answer:confusing

Step-by-step explanation:

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= Initial Knowledge Check Rewrite the expression by factoring out (y+9). 3y^2 (y + 9) + 7(y+9)​
alex41 [277]

Answer:

3y {}^{2} (y + 9) + 7(y + 9) \\  = (y + 9)(3y { }^{2}  + 7)

6 0
2 years ago
Giovanni bought 30 shares of Stock XYZ at the close price of $6.31. He
Diano4ka-milaya [45]

Answer:

Use the explantion to answer your question

Step-by-step explanation:

Amount he paid for first 20 shares

= $25 + (20 x $10.51)

= $25 + $210.20

= $235.20

Amount he paid for next 20 shares

= $25 + (20 x $8.93)

= $25 + $178.60

= $203.60

Thus, total amount paid

= $235.20 + $203.60

= $438.80

3 0
2 years ago
Read 2 more answers
Perform the operation.(−5x −9x+6)+(6x +10)
a_sh-v [17]

Answer:

-10x + 16

Step-by-step explanation:

Combine Like terms

8 0
3 years ago
The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in
Stolb23 [73]

Answer:

ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75

±0.75 ounce

Step-by-step explanation:

Assuming this complete question: The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in that state. To do this, they have selected a random sample of 300 people from the designated population. The following results were recorded: xbar=34.5 ounces, s=7.9 ounces Given this information, if the leaders wish to estimate the mean milk consumption with 90 percent confidence, what is the approximate margin of error in the estimate?

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=34.5 represent the sample mean

\mu population mean (variable of interest)

s=7.9 represent the sample standard deviation

n=300 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=300-1=299

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,199)".And we see that t_{\alpha/2}=1.653

And the margin of error is given by:

ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75

±0.75 ounce

4 0
3 years ago
Read 2 more answers
Need answer ASAP
vazorg [7]

Answer:

subject?

Step-by-step explanation:

6 0
3 years ago
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