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Blababa [14]
2 years ago
5

Which statement best conveys how the author's viewpoint changes in the passage.

SAT
1 answer:
fiasKO [112]2 years ago
8 0

Answer: His ability to describe the river with precise language improves as he gains more skills in steamboating . 

Explanation:

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In the context of the second stanza, the near rhyming of "mended" (line 5) and "tendered" (line 8) serves to depict a relationsh
AlladinOne [14]

In any given poem, we can see that the use of rhyme can be used to show the relationship between lines so that the reader can better understand the line and message behind it/

<h3>What is a Stanza?</h3>

This refers to the group of lines which forms a metrical unit in a poem.

<h3>What is Rhyme?</h3>

This refers to the use of similar sounding words together in a given line and they can rhyme in a particular pattern.

Please note that your question is incomplete so I gave you a general overview to help you get a better understanding of the concept,

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7 0
2 years ago
Point e is drawn on the graph so that line ef is parallel to line cd. If the coordinates of point e are (, y), what is the value
netineya [11]

Based on the graph given, it can be deduced from the computation that the value of y will be -8.

Point C is given as (-10 , -2)  and D = (10 , 6)

The Slope of line CD = ( 6 - (-2) /( 10 - (-10) =  8/20  = 2/5

Since EF is parallel to line CD , the slope of EF = 2/5

Equation  y  = (2/5)x  + c

5y = 2x + 5c

It passes through F ( 6 , -4)

= 5(-4) = 2*6  + 5c

= -20 = 12 + 5c

5c = -32

5y = 2x - 32

Point E ( - 4 , y)

5y = 2(-4) - 32

5y = -8 - 32

5y = -40

y = -8

Therefore, the value of y is -8.

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8 0
2 years ago
Determine the empirical formula of a compound containing 47. 37 grams of carbon, 10. 59 grams of hydrogen, and 42. 04 grams of o
Effectus [21]

Considering the definition of empirical formula, the empirical formula is C₃H₈O₂ and the molecular formula is C₉H₂₄O₆.

<h3>Definition of empirical formula</h3>

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

<h3>Empirical formula in this case</h3>

In this case, you have:

  • Carbon (C): 47.37 grams
  • Hydrogen (H): 10.59 grams
  • Oxygen (O):  42.04 grams

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

  • Carbon (C): \frac{47.37 grams}{12 \frac{g}{mole} }= 3.95 moles
  • Hydrogen (H): \frac{10.59 grams}{1 \frac{g}{mole} }= 10.59 moles
  • Oxygen (O):  \frac{42.04 grams}{16 \frac{g}{mole} }= 2.63 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

  • Carbon (C): \frac{3.95 moles}{2.63 moles }= 1.5
  • Hydrogen (H): \frac{10.59 moles}{2.63 moles }= 4
  • Oxygen (O):  \frac{2.63 moles}{2.63 moles }= 1

Finally, since in the empirical formula the numbers of moles must be expressed in whole numbers, the ratio of atoms is multiplied by some number with which everything is obtained in simple whole numbers (in this case by 2):

  • Carbon (C): 1.5× 2= 3
  • Hydrogen (H): 4× 2= 8
  • Oxygen (O):  1× 2= 2

Therefore the C: H: O mole ratio is 3: 8: 2

Finally, the empirical formula is C₃H₈O₂.

<h3>Molecular formula</h3>

To obtain the molecular formula you must relate its molecular weight (PMc) with the molecular weight of the empirical formula (PMfe).

PMfe= PM (C₃H₈O₂)= 76 g/mole

The molar mass of the compound (PMc) was determined to be 228.276 g/mol. Dividing this mass PMc by the molar mass of the empirical formula PMfe gives:

228.276 g/mol ÷ 76 g/mole= 3

This means that in the molecular formula there are 3 unit formulas (empirical formulas), so it is necessary to multiply the number of all atoms by 3.

Then, the molecular formula is C₉H₂₄O₆.

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What is migration?
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The most likely answer I option 1
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Ummmmmmm I’m not sure just quizlet it. Trust me it helps me A lot
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