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lina2011 [118]
4 years ago
12

Darin is 4 ft. 10 in. tall. His brother is 68 in. tall. How many in. taller is Darin's brother than Darin

Mathematics
2 answers:
HACTEHA [7]4 years ago
8 0
So first, convert 4 ft. 10 in. into feet.
The equation is 4(12)+10 since there are 12 inches in a foot. 
This would get you 58 inches.
Now his brother is 68 inches so subtract. 
68-58=10. 

Answer: Darin's brother is 10 inches taller than Darin. 

ella [17]4 years ago
5 0
He is 10 inches taller than his brother
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Orlov [11]
Below is the solution: 

A(final)=16cm^2 ds/dT=6 da/dT=? 

<span>A=(s)^2 A=16cm^2 , s=sqrt(A) , s=sqrt(16) , s=4cm </span>

<span>da/dT=2(s)(6cm/sec) , da/dT=12cm/sec(s) , da/dT=12cm/sec (4cm) 
</span>
<span>Answer should be da/dT=48cm^2/sec
</span>
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

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