Pleaseee help me w dis asap!!
1 answer:
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Answer:
Step-by-step explanation:
(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.
(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.
(C) Example of a second order linear ODE:
M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)
The equation will be homogeneous if K(t)=0 and heterogeneous if
Example of a second order nonlinear ODE:
(D) Example of a nonlinear fourth order ODE:
Answer:
A′B′ and AB are equal in length.
Step-by-step explanation:
Given that the location of the points are at A(1, 3) and B(5, 3).
Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, rotation, translation and dilation.
Rigid transformation are transformation that preserves the shape and size when performed. Types of rigid transformation are reflection, rotation, translation.
Hence if AB is rotated 270 degrees counterclockwise about the origin to form A′B′, both A′B′ and AB are equal in length because rotation is a rigid transformation.
If A(x,y) is rotated 270 degrees counterclockwise about the origin, it becomes A'(y,-x).
Hence if AB is rotated 270 degrees counterclockwise about the origin to form A'(3, -1), B'(3, -5)