1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alenkasestr [34]
2 years ago
8

Halp pls, check the points it should be worth it :'))

Mathematics
2 answers:
tresset_1 [31]2 years ago
6 0
The first pair isn’t equivalent because x in -15+x sums up to -14 and the x in -x-15 sums up to -16.
The second pair is equivalent because they both end up with -33 as the quotient.
Rudik [331]2 years ago
3 0

Answer:

Step-by-step explanation:

1) For the first one, x is positive and -15 is negative

   If you were to replace x with 1 we would get an answer of -14

   For the second one, x is negative and -15 is negative

   If you were to replace x with -1 you would get -16
So they are not equivalent!

2) For the second one, x is positive and -33 is negative

Since it is division it would not matter which one is negative, it would have the same outcome

If you were to replace x with 1, for the first one the answer would be -33/1 which is -33.

For the second one the answer would be 33/-1 which is also -33

So they are equivalent!

You might be interested in
<img src="https://tex.z-dn.net/?f=8%3D%5Cfrac%7B5x-1%7D%7B3%7D" id="TexFormula1" title="8=\frac{5x-1}{3}" alt="8=\frac{5x-1}{3}"
alukav5142 [94]

Answer:

x = 5

Step-by-step explanation:

Given

8 = \frac{5x-1}{3}

Multiply both sides by 3 to clear the fraction

24 = 5x - 1 ( add 1 to both sides )

25 = 5x ( divide both sides by 5 )

x = 5

4 0
4 years ago
Read 2 more answers
Help im stuck and my pullcrap ahh teacher not her to help and she got me do ixls
marysya [2.9K]

Answer:

c=4

Step-by-step explanation:

c=23

3 0
3 years ago
Camille takes a rock-climbing
hjlf

Answer:

Step-by-step explanation:

165/3=55 feet

7 0
3 years ago
A new school has x day students and y boarding students.
guapka [62]

Given:

The fees for a day student are $600 a term.

The fees for a boarding student are $1200 a term.

The school needs at least $720000 a term.

To show:

That the given information can be written as x + 2y\geq 1200.​

Solution:

Let x be the number of day students and y be the number of boarding students.

The fees for a day student are \$600 a term.

So, the fees for x day students are \$600x a term.

The fees for a boarding student are \$1200 a term.

The fees for y boarding student are \$1200y a term.

Total fees for x day students and y boarding student is:

\text{Total fees}=600x+1200y

The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.

600x+1200y\geq 720000

600(x+2y)\geq 720000

Divide both sides by 600.

\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}

x+2y\geq 1200

Hence proved.

3 0
3 years ago
William is thirty-two years older than his son Aaron. In ten years William will be three times as old as Aaron. How old is Aaron
Inga [223]
Aaron should be about 30 years old
5 0
4 years ago
Read 2 more answers
Other questions:
  • A number cube is rolled with these results: 64 ones, 67 twos, 73 threes, 59 fours, 72 fives, and 71 sixes. What is the experimen
    11·2 answers
  • In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead. Construct 90% confiden
    5·1 answer
  • What is the21st term of -3,2,7​
    7·2 answers
  • Please help me!
    11·1 answer
  • The area of a round table is 1.13 m2. Find the radius length of
    15·1 answer
  • ayuda !! Es la representación gráfica de una variable cuantitativa continua que agrupa intervalos de clases y es representada en
    15·1 answer
  • PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELPPPPPPPPPPPPPPPPPPPPPPPPLPPPPPPPPPPPPPPPPPPPPPPPPP I SWEAR I DO ANYTHING JUST PLZZZZZZZZZZZZZ
    13·1 answer
  • Find the True statement
    12·2 answers
  • Can you help me please
    15·1 answer
  • Please help!!!!!!!!!
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!