Answer:
The probability that the parcel was shipped expressed and arrived the next day = 0.2375 .
Step-by-step explanation:
We are given that a certain delivery service offers both express and standard delivery.
Let Proportion of parcels sent by standard delivery, P(
) = 0.75
Proportion of parcels sent by express delivery, P(
) = 0.25
Let <em>event B = Parcel arriving the next day</em>
Also, Probability of parcel arriving the next day given it was sent through standard delivery, P(B/) = 0.8
Probability of parcel arriving the next day given it was sent through express delivery, P(B/) = 0.95
Now, Probability that the parcel was shipped expressed and arrived the next day = P() * P(B/) = 0.25 * 0.95 = 0.2375 .
Answer:
Margin of Error decreases
Pvalue decreases
Power increases
Step-by-step explanation:
The margin of error decreases as sample size increases given the same level of confidence, hence, the interval gets narrower.
The margin of error = (Zcritical * σ/√n) ; where, n is the denominator, as the denomination increases, the obtained value will decrease, hence, the margin of error.
When we have a false H0, then we expect a statistical result which will reject H0, with all facts remaining unchanged , increase in sample size n, will lead to decrease in Pvalue, because a lower P value increases the significance of statistical test needed to reject H0.
The power of a fixed level test when the null hypothesis is true, higher power is required to reject the null , increasing n will increase the probability of rejecting H0, by increasing the power of a fixed level test.
Answer:
300
Step-by-step explanation:
Since 225 is 75% of a whole, write the proportion such that 225 corresponds to 75% and x, the number we're searching for, corresponds with 100%
Cross multiply to solve and divide by 75 to isolate x:
225 x 100 = 75x
22500 = 75x
300 = x
Hello :
<span>the linear function has form : y = ax </span>
