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Lerok [7]
2 years ago
8

Ms. Smith wants to do a statistical analysis on students' final examination scores in her math class for the past year. Should s

he consider her data to be a population data set or a sample data set?
Mathematics
1 answer:
Allushta [10]2 years ago
4 0

\tt{Hello~There!}

Answer:

\tt{Ms.~ Smith~ should~consider~ her~ data~ as~ a~ population~ data~ set.

}

Step-by-step explanation:

  • <em>Take into account that a population data set contains all members of the group and a sample data set contains only a subpart of the group.</em>

<em />

  • <em>In this case, Ms. Smith can take the scores of all students of the math class, due to this group is not enough big to consider to take a subpart.</em>

<em />

<u><em>Hence, Ms. Smith should consider her data as a population data set.</em></u>

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(a + b)(a ² - ab + b ²)
erastova [34]
Hi there!

You can use distributive property to solve this equation.

These are the list of terms you have to multiply :
a × a² = a³
a × -ab = -a²b
a × b² = ab²
b × a² = a²b
b × -ab = -ab²
b × b² = b³

add all of those terms...
a³ - a²b + ab² +a²b -ab² + b³
simplify by adding like terms... (- a²b + a²b , ab² - ab²)

a³ + b³

Hope this helped!! :)
4 0
3 years ago
PLZZZ HELP WILL GIVE BRAINN
Hatshy [7]

Answer:

Whole numbers: 56

Rational numbers: 1/3

Integer: -5

Irrational numbers: 1.17513698

Natural numbers: 0

4 0
3 years ago
Find the center and radius of the circle.<br> (x + 3)2 + (y + 4)2 =9
Tpy6a [65]

The general equation for any circle with its center at point (a, b) is

                 (x - a)² + (y - b)²  =  (radius)²

So the circle in the question is centered at (-3, -4), and its radius is  3 .

7 0
3 years ago
George walked on a treadmill 16 3/4 miles over 4
slamgirl [31]

Answer:

4 3/16 miles a day

Step-by-step explanation:

16 3/4 miles in 4 days

Divide 16 3/4 by 4

16 3/4 = 67/4

4 = 4/1

To divide you multiply by the reciprocal(flip of the numerator and denominator)

67/4 ÷ 4 = 67/4 x 1/4 = 67/16

67/16 = 4 3/16

If my answer is incorrect, pls correct me!

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5 0
2 years ago
What is the inverse and restricted domain of the equation 8x^2-3
kari74 [83]

Answer:  \bold{y=\pm \dfrac{\sqrt{2(x+3)}}{4},\qquad x\neq -3}

<u>Step-by-step explanation:</u>

y = 8x² - 3            (Restriction: none -  x is All Real Numbers)

The inverse is when you swap the x's and y's and then solve for y

x = 8y² - 3            <em>swapped the x and y</em>

x + 3 = 8y²           <em>added 3 to both sides</em>

\dfrac{x+3}{8}=y^2           <em>divided both sides by 8</em>

\sqrt{\dfrac{x+3}{8}}=\sqrt{y^2}           <em>square rooted both sides</em>

\pm \sqrt{\dfrac{x+3}{8}}=y           <em>simplified</em>

\pm \sqrt{\dfrac{x+3}{8}\bigg(\dfrac{2}{2}\bigg)}=y           rationalized the denominator

\pm \sqrt{\dfrac{2(x+3)}{16}}=y           <em>simplified</em>

\pm \dfrac{\sqrt{2(x+3)}}{4}=y           <em>simplified</em>

<u>Restriction:</u>

The radical <em>(inside the square root sign)</em> cannot be negative

→  2(x + 3) ≥ 0

      x + 3 ≥ 0         <em>divided both sides by 2</em>

      x       ≥ -3         <em>subtracted 3 from both sides</em>



4 0
3 years ago
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