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Lina20 [59]
3 years ago
12

HELP ASAP WILL GIVE 100 POINTS. Solve for x. 89(54x−36)+2=−34(−40+16x)+90x

Mathematics
1 answer:
PolarNik [594]3 years ago
3 0

Solution:

<u>Simplify the equation and solve.</u>

  • 89(54x − 36) + 2 = −34(−40 + 16x) + 90x
  • => 4806x − 3204 + 2 = 1360 - 544x + 90x
  • => 4806x = 1360 - 454x + 3202
  • => 5260x = 4562
  • => x = 4562/5260 = 2281/2630

The solution to the problem is 2281/2630.

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Umm im not sure maby like 1+1 or sum
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3 years ago
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1.
OlgaM077 [116]

Answer:

<h3>           A.   A = 66π cm² ≈ 207.35 cm²</h3><h3>           B.  No, will not. {will be less than double}</h3><h3>           C.  No, will not. {will be more than double}</h3>

Step-by-step explanation:

<h3>A.</h3>

h = 8 cm,  r = 3 cm

A = 2×πr² + 2πr×h = 2πr×(r + h)

A = 2π×3×(3 + 8) =  66π cm² ≈ 207.35 cm²

<h3>B.</h3>

h = 2×8 = 16 cm ,      r = 3 cm ,   2×66π = 132π cm²

A = 2π×3×(3 + 16) =  114π cm² ≠ 132π cm²  

<h3>C.</h3>

h = 8 cm ,        r = 2×3 = 6 cm  ,   2×66π = 132π cm²

A = 2π×6×(6 + 8) =  168π cm² ≠ 132π cm²    

4 0
3 years ago
Please help me.... Thanks​
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Answer:

-7//40

Step-by-step explanation:

5 0
3 years ago
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Which choice is equivalent to the product below when x&gt;0 ?
Rzqust [24]

Answer: x/3 ==> C

Step-by-step explanation:

(2x/3)^1/2 * (x/6)^1/2=

(2x/3 * x/6)^1/2=

(2x^2/18)^1/2=

(2x^2)^1/2 / 18^1/2=

(2x^2)^1/2 / (2*9)^1/2=

(2x^2)^1/2 / 3*2^1/2=

2^1/2 * (2x^2)^1/2 / 3*2=

(2(2x^2))^1/2 / 6=

(4x^2)^1/2 / 6=

4^1/2 * (x^2)^1/2 / 6=

2x/6=x/3 ==> C

3 0
2 years ago
On Martin's first stroke, his golf ball traveled 4 5 5 4 ​ start fraction, 4, divided by, 5, end fraction of the distance to the
faltersainse [42]

Answer:

0.395 kilometers

Step-by-step explanation:

Please consider the complete question.

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole. On his second stroke, the ball went into the hole. Martin was standing 79 meters from the hole as he took his second stroke. How many kilometers from the hole was Martin when he started?

Let x represent the distance between hole and start point.

In 1st stroke ball traveled 4/5 of the distance, so 1/5 of the distance was remaining from 2nd stroke to hole. This means the 1/5 of whole distance between start point and hole is equal to 79 meters.

We can represent this information in an equation as:

\frac{1}{5}x=79

\frac{1}{5}x\cdot 5=79\cdot 5

x=395

Since our distance is in meters, so we will convert 395 meters into kilometers by dividing by 1000.

395\text{ meters}=\frac{395}{1000}\text{ km}=0.395\text{ km}

Therefore, Martin was 0.395 kilometers from the hole, when he started.

3 0
3 years ago
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