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trasher [3.6K]
3 years ago
5

2) Poe Tayto wants to

Mathematics
1 answer:
adoni [48]3 years ago
7 0

Answer:

It will take 8.73 years.

Step-by-step explanation:

Giving the following information:

Initial investment (PV)= $1,000

Future value (FV)= $1,500

Interest rate (i)= 4.75% compounded annually

<u>To calculate the time required for the initial investment to reach the objective, we need to use the following formula:</u>

<u></u>

n= ln(FV/PV) / ln(1+i)  

n= ln(1,500/1,000) / (1.0475)

n= 8.73

It will take 8.73 years.

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O persoană avea 1200 lei și a cheltuit 15% din ei pentru o camașă si 40% din ei pe o pereche de pantofi.Ce sumă i-a rămas?
Katarina [22]

Answer:

540 lei

Step-by-step explanation:

Pasul 1

Suma cheltuită pe cămașă se calculează astfel:

1200 lei × 15%

= 1200 lei × 15/100

= 180

Pasul 2

Suma cheltuită pentru o pereche de pantofi se calculează astfel:

1200 lei × 40%

= 1200 lei × 40/100

= 480 lei

Pasul 3

Suma rămasă este calculată ca:

Suma totală - (Suma cheltuită pe cămașă + Suma cheltuită pe încălțăminte)

1200 lei - (180 + 480) lei

1200 lei - 660 lei

= 540 lei

3 0
3 years ago
The graph of y=2x^2-4x+2 has a y-intercept of (0,1).<br> A. True<br> B. False
astra-53 [7]
False. Set x = 0 and find y.

y = 2(0)^2 - 4(0) + 2
y = 0 - 0 + 2
y = 2

The y-intercept is (0, 2), not (0, 1).
8 0
4 years ago
What’s the work and answer for this? Someone please tell me
Yuliya22 [10]

Answer:

3

Step-by-step explanation:

3 0
3 years ago
Hellp pls. This is not a test, so pls do not report.
SashulF [63]
B is the correct answer

7 0
3 years ago
Mateo is culturing bacteria that have a growth rate of 5.3% per hour. If the current population is 38,762 bacteria, how many bac
Taya2010 [7]

..Given:

\begin{gathered} a=38762 \\ r=5.3\%=\frac{5.3}{100}=0.053 \\ t=20 \end{gathered}

To Determine: The number of bacteria after 20 hours

Using the future value formula for growth rate

\begin{gathered} P_a=P_c(1+r)^t \\ P_a=(Bacteria,final,population) \\ P_c(Bacteria,current,population)=38762 \\ r(rate)=0.053,t(time,in,hour)=20 \end{gathered}

Therefore

\begin{gathered} P_a=38762(1+0.053)^{20} \\ P_a=38762(1.053)^{20} \\ P_a=38762(2.809101) \\ P_a=108886.39 \\ P_a\approx108886 \end{gathered}

Hence, population of bacteria in 20 hours is 108,886

8 0
2 years ago
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