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Montano1993 [528]
2 years ago
6

a warehouse has 1,203 shirts to send 3 stores, If each store gets the same number of shirts , how many shirts will go to each st

ore
Mathematics
1 answer:
antiseptic1488 [7]2 years ago
7 0

Answer:

401 shirts

Step-by-step explanation:

1203 divided by 3 equals to 401

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Answer:

3

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6 0
3 years ago
Write an algebraic expression that represent the sum of 8 and two-third of x?
lesantik [10]

We have to sum 8 and two-third of x, so we must multiply x by 2/3 and sum it with 8,

thus, the expression is

\frac{2}{3}x+8

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1 year ago
What are the values of a 1 and r of the geometric series? 1 3 9 27 81 a 1 = 1 and r = one-third a 1 = one-third and r = 1 a 1 =
Paha777 [63]

Answer:

a₁ = 1

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
Explain how you can determine the number of real number solutions of a system of equations in which one equation is linear and t
DerKrebs [107]

Isolate one variable in the system of equations. Use substitution to create a one-variable equation. Then, set the quadratic equation equal to zero and find the discriminant. If the discriminant is negative, then there are no real number solutions. If the discriminant is zero, then there is one real number solution. If the discriminant is positive, then there are two real number solutions.

4 0
3 years ago
Read 2 more answers
the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t
Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count Pr(A|B).

Use formula for conditional probability:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

1. The event A\cap B consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event A\cap B is

Pr(A\cap B)=\dfrac{1}{20}.

2. The event B consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event B is

Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.

3. Then

Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.

Answer: \dfrac{1}{2}.

5 0
3 years ago
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