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vagabundo [1.1K]
2 years ago
9

What is 6 2/3 in radical form

Mathematics
1 answer:
lord [1]2 years ago
7 0
6 sqrt 6 6^(1 + 1/2) = 6 sqrt 6.
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What is the equation for the line that passes through the point (-7,-7) and has a slope of 1?
sladkih [1.3K]

Answer:

Step-by-step explanation:

4 0
3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
yKpoI14uk [10]

Answer:

Confidence Interval in 95% confidence level for the quality rating is (6.06,7.46)

Step-by-step explanation:

Confidence Interval can be calculated using the formula M±ME where

  • M is the mean of the sample
  • ME is the margin of error in a given confidence level

Using the sample obtained from 50 business travelers we get

  • Mean of the sample is 6.76
  • standard deviation of the sample is 2.526

Margin of error (ME) around the mean using the formula

ME=\frac{z*s}{\sqrt{N} } where

  • z is the corresponding statistic in 95% confidence level (1.96)
  • s is the standard deviation of the sample (2.526)
  • N is the sample size (50)

Using the numbers in the formula we get:

ME=\frac{1.96*2.526}{\sqrt{50} } ≈ 0.70

Then the confidence interval becomes 6.76±0.70

6 0
3 years ago
In 1985, the average ACT score was 18 with a standard deviation of 6. Also in 1985, the average SAT score was
lord [1]

The ACT score was better since the z-score of the ACT is greater than the z-score of the SAT. Then the correct option is B.

<h3>What is a normal distribution?</h3>

It is also called the Gaussian Distribution. It is the most important continuous probability distribution. The curve looks like a bell, so it is also called a bell curve.

The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.

The z-score is given as

\rm z = \dfrac{x - \mu }{\sigma}

In 1985, the average ACT score was 18 with a standard deviation of 6.

Also in 1985, the average SAT score was 500 with a standard deviation of 100.

Dr. Robertson took both tests in 1985 and scored a 26 on the ACT and a 620 on the SAT.

Then the z-score of the ACT will be

\rm z = \dfrac{26 - 18}{6}\\\\z = 1.3333

Then the z-score of the SAT will be

\rm z = \dfrac{620 - 500}{100}\\\\z = 1.2

Then the ACT score was better since the z-score of the ACT is greater than the z-score of the SAT.

More about the normal distribution link is given below.

brainly.com/question/12421652

#SPJ1

6 0
2 years ago
9. Which correctly describes the root of the following cubic equation?
katrin2010 [14]
Option B is the answer and that because the photo below
3 0
3 years ago
Find the second derivative y= x^2lnx
Dimas [21]
First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx

now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
         1+2+2lnx
         3+2lnx is the answer


3 0
3 years ago
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