Given:
Endpoints of a segment are (0,0) and (27,27).
To find:
The points of trisection of the segment.
Solution:
Points of trisection means 2 points between the segment which divide the segment in 3 equal parts.
First point divide the segment in 1:2 and second point divide the segment in 2:1.
Section formula: If a point divides a line segment in m:n, then

Using section formula, the coordinates of first point are



Using section formula, the coordinates of first point are



Therefore, the points of trisection of the segment are (9,9) and (18,18).
Answer:
0.57142
Step-by-step explanation:
A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?
We are told that the Mean and Standard deviation = 10°C
We convert to Fahrenheit
(10°C × 9/5) + 32 = 50°F
Hence, we solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 59 °F
μ is the population mean = 50 °F
σ is the population standard deviation = 50 °F
z = 59 - 50/50
z = 0.18
Probability value from Z-Table:
P(x ≤59) = 0.57142
The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit
is 0.57142
Answer:
Step-by-step explanation:
The equation representing the price of gas for the years after 2000 is expressed as
y = 1.26(1.10)^x
Where x = 0, 2, 4, 6, 8, and 10 represent these years : 2000, 2002, 2004, 2006, 2008, and 2010, the table would be
1) x = 0(2000)
y = 1.26(1.10)^0
y = 1.3
2) x = 2(2002)
y = 1.26(1.10)^2
y = 1.5
3) x = 4(2004)
y = 1.26(1.10)^4
y = 1.8
4) x = 6(2004)
y = 1.26(1.10)^6
y = 2.2
5) x = 8(2006)
y = 1.26(1.10)^8
y = 2.7
6) x = 10(2008)
y = 1.26(1.10)^10
y = 3.3
Answer:
2020
Step-by-step explanation:
2020
The answer is 99.2u squared y squared