Question

In 1990, there were 4,298,000 Mexican immigrants living in the United States. In 2000 this number had increased to 7,858,000. Find the percent of increase to the nearest tenth. a. 69.6% c. 82.8% b. 101% d. 90.2%

Answer 1

Answer:

c

Step-by-step explanation:

In thousands:

$7858 - 4298 = 3560$

$\frac{3560}{4298} = .828$

$4298 \times 1.828 = 7857$