Question

The length of a rectangle is 5 more than twice its width. if the perimeter of the rectangle is 82 centimeters, find its length and its width.

Answer 1

P = 2L + 2W, keep that in mind (W=width, L=length)

Just fill it in. 82=2(5+2w) + 2w. First solve for w.

82 = 10+ 10w + 2w,

82 = 10 + 12w. Now subtract the 10 from both sides, and get:

72 = 12w, now divide both sides by 12, and get:

6 = w.

W is 6.

Now to solve for L, go back to the problem we had, L = 5 + 2w. Fill in w,

L = 5 + 2(6), and then it is L = 5 + 12.

It is a simple addition equation now.

L = 17, W = 6