Answer:

Step-by-step explanation:
My favorite way to go at this is to look at a graph. It shows the vertex at (-2, -11). Since the leading coefficient is 2, this means the roots are ...

where the 2 in the denominator of the radical is the leading coefficient.
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You can also use other clues:
- the axis of symmetry is -b/(2a) = -8/(2(2)) = -2, so answer choices C and D don't work
- the single change in sign in the coefficients (+ + -) tells you there is one positive real root, so answer choice B doesn't work.
The first answer choice is the only one with values symmetrical about -2 and one of them positive.
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You may be expected to use the quadratic formula:

13 floors is the correct answer
Option D:
ΔCAN ≅ ΔWNA by SAS congruence rule.
Solution:
Given data:
m∠CNA = m∠WAN and CN = WA
To prove that ΔCAN ≅ ΔWNA:
In ΔCAN and ΔWNA,
CN = WA (given side)
∠CNA = ∠WAN (given angle)
NA = NA (reflexive side)
Therefore, ΔCAN ≅ ΔWNA by SAS congruence rule.
Hence option D is the correct answer.
Answer:
65
Step-by-step explanation:
6+5=11
Answer:
B
Step-by-step explanation:
- 2 | 2 2 - 2 4
↓ - 4 4 - 4
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2 - 2 2 0 ← remainder
Since the remainder = 0 then (x + 2) is a factor
quotient = 2x² - 2x + 2