Area of part 1:A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2Area of part 2:A2=length*width=(8+2)*1=10 ft2Area of part 3:A3=length*width=8*2=16 ft2
Total shaded area : A1+A2+A3=41 ft2Total area of the reactangle : A=16*8=128 ft2Total area of the nonshaded region : 128-41=87 ft2
Answer:
No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.
For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.
2
in.
+
3
in.
=
5
in.
5
in.
<
6
in.
For a triangle with sides 3 in., 4 in. and 5 in. which can form a triangle:
3 + 4 = 7 which is greater than 5
3 + 5 = 8 which is greater than 4
4 + 5 = 9 which is greater than 3
Step-by-step explanation:
Step-by-step explanation:
12x + 3(x - 4) + 2x
17x-12
HOPE IT HELPS U
Answer:
C; None of the above.
Step-by-step explanation:
Pretend x=1, y=0, and z=2.
You have to match an answer to 1+0-2 (equals to -1).
The first equation would be 2+0+1. When you add them all together you get 3, and that isn't equivalent to -1, so therefore this one is not the answer.
The second equation becomes 1+2+0, and when you solve for the answer, you see that the answer is also 3, and so we can conclude that neither A or B matches with the equation above, so the answer is C, None of the above.
