If the relative frequency of a train being late is 0.15 how often could you expect the train to be late in 100 days?
1 answer:
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X 
38 -> 24x
x > 38 -> 31(x-38) + 912
912 = 24*38 (You will have to have 38 hours to be able to be in this part of the piece wise function)
x > 38 -> 31(x-38) + 912
912 = 24*38 (You will have to have 38 hours to be able to be in this part of the piece wise function)