Answer:
Binding of glucose to hexokinase causes a conformational change in the enzyme. This is an example of the<u> induce-fit </u>model of enzyme catalysis.
Explanation:
The induce- fit model is generally the most accepted theory for enzyme catalysis. This theory states that the active site of an enzyme is not always a perfect fit for a substrate. The substrate induces changes in the active site so that it can fit into the active site. This theory is contrary to the theory of lock and key model, which stated that substrates exist as a perfect match for particular active sites of an enzyme.
<span>Option 1: Sunlight is the energy source for plant photosynthesis.
True: In photosynthesis, plants convert light energy from the sun to chemical energy in the form of glucose.
Option 2: Chlorophyll is contained in organelles called chloroplasts.
True: Chlorophyll in the chloroplasts is what allows many wavelengths of light for be absorbed and used for photosynthesis.
Option 3: A by-product of photosynthesis is carbon dioxide.
False: Plants require carbon dioxide to create glucose, and produce oxygen as a by-product.
Option 4: Roots have tiny root hairs that maximize the plant's ability to absorb water.
True: Root hairs are very important for the absorption of nutrients and water by plant roots. </span><span /><span>
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Answer:
Genotype ratio: 1, 1:1, 1:2:1
Phenotype ratio: 1, 3:1
Explanation:
Single gene pair cross is also known as monohybrid cross. This means that only one gene usually with two alleles is observed and it express one trait.
For example, if we name the gene for a certain trait with A, the possible genotypes are AA (dominant homozygous), aa (recessive homozygous) and Aa (heterozygous). Possible crosses are:
P: AA x AA
F1 : all of them are AA
The same is with aa x aa (all of the offspring are with aa genotype)
P: AA x Aa
F1: AA Aa AA Aa (genotype ratio 1:1) (phenotype ratio 3:1)
The same genotype ratio is in aa x Aa (offspring will have aa Aa aa Aa-(genotype ratio 1:1) (phenotype ratio 1:1)
P: Aa x Aa
F1: AA Aa Aa aa (genotype ratio 1:2:1) (phenotype ratio 3:1)
P: AA x aa
F1: Aa Aa Aa Aa (1)
Answer:
The solubility of any substance in water depends on its polarity. The polar molecule dissolves more easily in the water than the non polar molecule. Amino acids have different polarity at different pH.
(a) (Lys-Ala)3 : The (Lys-Ala)3 contain more positive charge and highly polar the at pH 7 as compared with the (Gly)20 that remains uncharged and has less polarity.
(b) (Glu)20 :This amino acids negatively charged at pH 7 and highly polar than the (Phe-Met)3 which is non polar or less polar and hence least soluble in water.
(c) (Asn-Ser-His)5 is highly polar at pH 3 as compared with the (Ala-Asp-Gly)5 that contains the carboxylate groups of Asp residues that are partially neutral. The (Asn-Ser-His)5 contains = the imidazole groups of His residues are fully polar and soluble in water.
(d) (Asn-Ser-His)5 is polar at pH 6.0 because both have polar side chains Ser but (Asn-Ser-His)5 is only partially partially protonated due to the His side chains. Thus, (Asn-Ser-His)5 is more soluble in water.
