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loris [4]
3 years ago
11

Please help me and hurry

Mathematics
1 answer:
myrzilka [38]3 years ago
4 0

Answer:

1; is 20 2 is 50 3 is 18 4 is 9 and 5 is 16

Step-by-step explanation:

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<h3>The Answer is:</h3>

1011000

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A carpenter had a piece of wood that was 15 feet in length. If he needs only 10 &amp;five twelfth feet of wood, then how much wo
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Answer:

12.5 feet

Step-by-step explanation:

He only needs 10/12 of a 15 foot long piece of wood. We need to find 10/12 of the length of the wood.

That is:

10/12 * 15 = 12.5 feet

He only needs 12.5 feet of the piece of wood.

7 0
4 years ago
The Alvin Secretarial Service procures temporary office personnel for major corporations. They have found that 60% of their invo
Hoochie [10]

Answer:

0.9942 = 99.42% probability that at least 6 of the invoices will be paid within ten working days

Step-by-step explanation:

For each invoice, there are only two possible outcomes. Either they are paid within 10 working days, or they are not. The probability of an invoice being paid within 10 working days is independent of other invoices. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

60% of their invoices are paid within ten working days.

This means that p = 0.6

A random sample of 18 invoices is checked.

This means that n = 18

What is the probability that at least 6 of the invoices will be paid within ten working days?

Either less than 6 are paid within 10 working days, or at least 6 are paid. The sum of the probabilities of these events is 1. So

P(X < 6) + P(X \geq 6) = 1

We want P(X \geq 6). So

P(X \geq 6) = 1 - P(X < 6)

In which

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.6)^{0}.(0.4)^{18} \approx 0

P(X = 1) = C_{18,1}.(0.6)^{1}.(0.4)^{17} \approx 0

P(X = 2) = C_{18,2}.(0.6)^{2}.(0.4)^{16} \approx 0

P(X = 3) = C_{18,3}.(0.6)^{3}.(0.4)^{15} = 0.0002

P(X = 4) = C_{18,4}.(0.6)^{4}.(0.4)^{14} = 0.0011

P(X = 5) = C_{18,5}.(0.6)^{5}.(0.4)^{13} = 0.0045

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0 + 0 + 0 + 0.0002 + 0.0011 + 0.0045 = 0.0058

Finally

P(X \geq 6) = 1 - P(X < 6) = 1 - 0.0058 = 0.9942

0.9942 = 99.42% probability that at least 6 of the invoices will be paid within ten working days

6 0
4 years ago
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