Answer: 30 6/29
Step-by-step explanation: 6132 \ 203 is 30 and 42/203. 42/203 simplified is 6/29
It was 65 degrees by lunch time.
Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
area of a triangle is 1/2 x base x height
base = 19
height = 3
19 *3 = 57
1/2 x 57 = 28.5 square ft.
Answer:
Option A is correct.
Solution for the given equation is, 
Step-by-step explanation:
Given that : 
Let 
then our equation become;
.....[1]
A quadratic equation is of the form:
.....[2] where a, b and c are coefficient and the solution is given by;

Comparing equation [1] and [2] we get;
a = 2 b = -1 and c =-1
then;

Simplify:

or


or
and 
Simplify:
y = 1 and
Substitute y = cos x we have;

⇒
and

⇒
The solution set: 
Therefore, the solution for the given equation
is, 