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2 years ago

Can someone help answer this for me? this does not make any sort of sense to me

Mathematics

1 answer:

IgorC [24]2 years ago

7 0

Solution:

Note that:

Triangle ABC ≅ Triangle FGH
AC = 30 units
CB = 10 units
BA = 35 units
FH = 18 units
HG = 6 units

Looking at both the triangles, we can say that:

FH = 3AC/5 = 3(30)/5 = 90/5 = 18 units
HG = 3BC/5 = 3(10)/5 = 30/5 = 6 units

We can do the same with AB and FG.

FG = 3AB/5 = 3(35)/5 = 3(7) = 21 units

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Each unit on the grid stands for one miles determine two ways to calculate the distance from josie's house to annies

Novosadov [1.4K]

I encountered this problem before but it had an accompanying image and list of answer choices.

I'll attach the image and include the list of options.

Each unit on the grid stands for one mile. Determine two ways to calculate the distance from Josie's house to Annie's house.
A) Distance Formula and Slope Formula
B) Midpoint Formula and Slope Formula
C) Distance Formula and Midpoint Formula
D) Distance Formula and Pythagorean Theorem

My answer is: D.) Distance formula and Pythagorean Theorem.

When looking at the image, I can visualize a right triangle. I'll simply get the measure of the long and short legs and solve for the hypotenuse.
Since the distance formula is derived from the Pythagorean theorem, it can be used to determine the distance from Josie's house to Annie's house.

8 0

2 years ago

The perimeter of a rectangular baking sheet is 58 inches and its area is 201.25 in.2. What are the length and width of the bakin

anzhelika [568]

Answer:

$Length=17.5\ in\\\\Width=11.5\ in$

Step-by-step explanation:

The formula for calculate the Area of a rectangle is:

$A=lw$

Where "l" is the lenght and "w" is the width.

And the formula for calculate the peimeter of a rectangle is:

$P=2l+2w$

Where "l" is the lenght and "w" is the width.

We know that the perimeter of the rectangular baking sheet is 58 inches and its area is 201.25 in². Then:

$A=201.25\ in^2\\\\P=58\ in$

The steps are:

1. Solve for the "l" from the formula $A=lw$ :

$A=lw\\\\l=\frac{A}{w}\\\\\l=\frac{201.25}{w}$

2. Substitute $l=\frac{201.25}{w}$ into the formula $P=2l+2w$ and solve for "w":

$58=2(\frac{201.25}{w})+2w\\\\58=\frac{402.5}{w}+2w\\\\58=\frac{402.5+2w^2}{w}\\\\58w=402.5+2w^2\\\\2w^2-58w+402.5=0$

Applying the Quadratic formula $x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$ , we get:

$x=w=\frac{-(-58)\±\sqrt{(-58)^2-4(2)(402.5)}}{2(2)}\\\\w_1=17.5\\\\w_2=11.5$

3. Substitute $w_1=17.5$ into $l=\frac{201.25}{w}$ :

$l=\frac{201.25}{17.5}=11.5$

4. Substitute $w_2=11.5$ into $l=\frac{201.25}{w}$ :

$l=\frac{201.25}{11.5}=17.5$

Therefore, since the value of the lenght of a rectangle must be greater that the value of the width, we can conclude that the lenght and the width of the rectangular baking sheet are:

$l=17.5\ in\\\\w=11.5\ in$