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kap26 [50]
3 years ago
14

Which expression is equivalent to StartFraction 7 Superscript 5 Over 7 squared EndFraction? (7 times 5) (7 times 2) (7 times 7 t

imes 7 times 7 times 7) (7 times 7) StartFraction 7 times 5 Over 7 times 2 EndFraction StartFraction 7 times 7 times 7 times 7 times 7 Over 7 times 7 EndFraction.
Mathematics
1 answer:
slavikrds [6]3 years ago
6 0

To solve the problem we will use the basic exponent properties.

<h3>What are Expressions?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

<h3>What are the basic exponent properties?</h3>
  • {a^m} \cdot {a^n} = a^{(m+n)}
  • \dfrac{a^m}{a^n} = a^{(m-n)}
  • \sqrt[m]{a^n} = a^{\frac{n}{m}}

The solution to the given expression is (7 \times 7 \times 7).

Given to us

  • \dfrac{7^5}{7^2}

<h3>Basic exponent properties,</h3>

To solve the problem we will use the basic exponent properties,

\dfrac{7^5}{7^2}

Using the property \dfrac{a^m}{a^n} = a^{(m-n)},

=\dfrac{7^5}{7^2}\\\\= 7^{(5-2)}\\=7^3\\=7 \times 7 \times 7

Hence, the solution to the given expression is (7 \times 7 \times 7).

Learn more about Expression:

brainly.com/question/13947055

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You and a friend play a game where you each toss a balanced coin. If the upper faces on the coins are both tails, you win $1; if
oksian1 [2.3K]

Answer:  The mean and variance of Y is $0.25 and $6.19 respectively.

Step-by-step explanation:

Given : You and a friend play a game where you each toss a balanced coin.

sample space for tossing two coins : {TT, HT, TH, HH}

Let Y denotes the  winnings on a single play of the game.

You win $1; if the faces are both heads

then P(Y=1)=P(TT)=\dfrac{1}{4}=0.25

You win $6; if the faces are both heads

then P(Y=6)=P(HH)=\dfrac{1}{4}=0.25

You loose $3; if the faces do not match.

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The expected value to win : E(Y)=\sum_{i=1}^{i=3} y_ip(y_1)

=1\times0.25+6\times0.25+(-3)\times0.50=0.25

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E(Y^2)=\sum_{i=1}^{i=3} y_i^2p(y_i)\\\\=1^2\times0.25+6^1\times0.25+(-3)^2\times0.5\\\\=0.25+1.5+4.5=6.25

Variance = E[Y^2]-E(Y)^2

=6.25-(0.25)^2=6.25-0.0625=6.1875\approx6.19

Hence, variance of Y = $ 6.19

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Answer:

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Step-by-step explanation:

The sequence is to multiply by -4. 24 times -4 = -96

6 0
3 years ago
Describe each step taken to solve the equation. Then, check the solution to see if it is valid. If it is not a valid solution, e
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Answer:

Step-by-step explanation:

given,

a) √x + 6 = 4                                                    

to solve the above equation subtract both side with 6

    √x + 6 - 6  = 4 - 6                  

                √x  = -2                  

squaring both side

                (√x)² = (-2)²              

                       x = 4            

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to solve the above equation subtract both side with 6

    ∛x + 6 - 6  = 4 - 6

                ∛x  = -2

cubing  both side

                (√x)³ = (-2)³

                      x = -8

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4 years ago
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