<span>In this expression, the variable ’t’ stands in for any possible value of seconds. Therefore, since you know how long it takes the object to fall in seconds, you can put this into the expression. 16 x (4^2) = 256. The distance is 256ft.</span>
The formula for area in terms of radius is
... A = πr²
Solving this for r, we get
... A/π = r²
... r = √(A/π) . . . . . formula for the radius
For your given area, the radius is approximately
... r = √(401.92/3.14) = √128 = 8√2
... r ≈ 11.3 . . . yards
The correct answer is A) g≥5
This is because when you look at an absolute value function, the constant at the end is the y value of the vertex. Since it is an absolute value equation, we know that the values can only go up. Therefore, it must be greater than or equal to the constant at the end (5)
1)5 2)6 3)17 because h(x)+k(x)=3x-1
To determine the answer of Part A draw the equilateral triangle and the to determine the coordinates of of the third charge use that triangle.
To calculate the gravitational field strength in part B from each of the charges use the following equation.
E=kcq/r2
If you would add those values then you can use the symmetry about the y axis to make the vector addition a litter easier.<span />
