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ch4aika [34]
2 years ago
7

Find the x (6x-27) (4x+7) =

Mathematics
2 answers:
Temka [501]2 years ago
6 0

Answer:

6x-27=0 or 4x+7=0

6x=27 4x=-7

x=27/6 x=-7/4

x=4,5 x=-1,75

There for : x=4,5 or x=-1,75

babunello [35]2 years ago
5 0

this question is wrong

(6X-27)(4X+7)=????

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A sled is being pulled with a force of 120 N at an angle of 35o with the horizontal. How far is the sled pulled if 1100 J of wor
natta225 [31]

Answer:11.2 m

Step-by-step explanation:

Given

Force Applied F=120 N

inclination \theta =35^{\circ}

Force has two components here i.e. F\cos \theta and F\sin \theta

F\cos \theta will will do work

Work done is given by force time displacement

W=120\cdot \cos 35\times s

1100=120\times \cos 35\times s

s=11.19\approx 11.2 m

7 0
3 years ago
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Leya [2.2K]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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Professor stan der Deviation can take one of two routes on his way home from work. On the first route, there are four railroad c
insens350 [35]

Answer:

A) He should take the route with 4 crossings

B) The probability that he took the 4 crossing route is 0.2158

Step-by-step explanation:

Lets call X the number of crossings he encounters, A if he takes route 1 and B if he takes route 2.

Note that X given A is a binomial random variable with parameters n = 4 p = 0.1, and X given B has parameters n = 2, p = 0.1

The probability that the Professor is on time on route 1 is equal to

P(X|A = 0) + P(X|A = 1) = 0.9⁴ + 0.9³*0.1*4 = 0.9477

On the other hand, the probability that the professor is on time on route 2 is

P(X|B = 0) = 0.9² = 0.81

Hence, it is more likely for the professor to be late on route 2, thus he should take the route 1, the one with 4 crossings.

B) Lets call L the event 'The professor is late'. We know that

P(L|A) = 1-0.9477 = 0.0524

P(L|B) = 1-0.81 = 0.19

Also

P(A) = P(B) = 1/2 (this only depends on the result of the coin.

For the Bayes theorem we know, therefore that

P(A|L) = \frac{P(L|A) * P(A)}{P(L|A)*P(A) + P(L|B)*P(B)} = \frac{0.0523*0.5}{0.0523*0.5 + 0.19*0.5 } = 0.2158

Hence, the probability that he took the 4 crossing route is 0.2158.

4 0
4 years ago
What is the average (arithmetic mean) of the first 90 measurements in a certain list of 92 measurements? (1) the average of the
marishachu [46]
The sum of all the measurements is just the average times the number.

\bar x = \frac{1}{n} \sum_{i=1}^n x_i

\sum_{i=1}^n x_i = n \bar x

So if the average of all 92 is 7 the sum of those is 92 \times 7

The average of the last two is 7.2 so their sum is 2 \times 7.2

That means the sum of the first 90 is 92 \times 7 - 2 \times 7.2

so the average of the first 90 is

 \dfrac{92 \times 7 - 2 \times 7.2}{90} = 6.99556 cm



7 0
3 years ago
What is the answer to this
Vlad1618 [11]
Pretty sure its 7 because x should equal 1 and since there put together like that you'd times it do it should be 4 then add 3 and its 7
8 0
4 years ago
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