3 years ago

What is the answer to this

1 answer:

8 0

Pretty sure its 7 because x should equal 1 and since there put together like that you'd times it do it should be 4 then add 3 and its 7

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grandymaker [24]

The mass of the first shipment at time t is
$m_{1}=100( \frac{1}{2} )^{ \frac{t}{10}}$

The mass of the second shipment at time t is
$m_{2}=100( \frac{1}{2} )^{ \frac{t-3}{10} }$

At time t, the ratio of m₁ to m₂ is
$\frac{m_{1}}{m_{2}} = \frac{100}{100}. \frac{(1/2)^{t/10}}{(1/2)^{(t-3)/10}} \\ = \frac{(1/2)^{t/10}}{(1/2)^{t/10}}. \frac{1}{(1/2)^{-3/10}} \\ = (1/2)^{3/10} \\ = 0.8123$

Therefore as a percentage,
$\frac{m_{1}}{m_{2}} =100*0.8123 = 81.23 \%$

Answer: B. 81.2%

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3 years ago

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Answer:

Step-by-step explanation: (dont trust me)

x^2 + (7)x +18

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2 years ago

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24000 is the answer

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The answer is 226.19 presisely

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Answer:

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Step-by-step explanation:

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