Ask question

Ask question

All categories

3 years ago

7

After all tryouts are completed, the school will be hosting a party for all the new athletes. At the party, hot dogs and hamburg

ers will be provided to all athletes and their guests, if they choose to bring a guest. The ratio of hot dogs purchased to number of guests is 1:0.8. Determine how many hot dogs you would need if 150 people attend the party. Explain how you found your answer.

1 answer:

erik [133]3 years ago

8 0

120 hotdogs would be served if 150 people attend the party.

<h3>Ratio</h3>

A ratio is the quantitative relationship between two value, showing how many times one number contains another.

The ratio of hot dogs purchased to number of guests is 1:0.8. For 150 people:

Number of hotdogs = 150 * 0.8/1 = 120 hotdogs

Therefore 120 hotdogs would be served if 150 people attend the party.

Find out more on Ratio at: brainly.com/question/2328454

You might be interested in

Need help asap!!<br> analyze the diagram below and answer the question that follows.

katrin2010 [14]

Answer:

D) cos^-1 (f/e)

Step-by-step explanation:

Since you only know two sides, DE = f, and DF = e, you need to use cosine to find the measure of ∠D.

Let x represent m∠D

cos x = f/e

To find x, take the inverse of cos, so:

cos^-1 (f/e) = x

5 0

3 years ago

The twice–differentiable function f is defined for all real numbers and satisfies the following conditions: f(0)=3 f′(0)=5 f″(0)

Vladimir79 [104]

$g(x)=e^{ax}+f(x)\implies g'(x)=ae^{ax}+f'(x)\implies g''(x)=a^2e^{ax}+f''(x)$

Given that $f'(0)=5$ and $f''(0)=7$ , it follows that

$g'(0)=a+5$

$g''(0)=a^2+7$

###

$h(x)=\cos(kx)f(x)+\sin x\implies h'(x)=-k\sin(kx)f(x)+\cos(kx)f'(x)+\cos x$

When $x=0$ , we have

$h(0)=\cos0f(0)+\sin0=f(0)=3$

The slope of the line tangent to $h(x)$ at (0, 3) has slope $h'(0)$ ,

$h'(0)=-k\sin0f(0)+\cos0f'(0)+\cos0=5+1=6$

Then the tangent line at this point has equation

$y-3=6(x-0)\implies y=6x+3$

###

Differentiating both sides of

$4x^2+y^2=48+2xy$

with respect to $x$ yields

$8x+2y\dfrac{\mathrm dy}{\mathrm dx}=2y+2x\dfrac{\mathrm dy}{\mathrm dx}$

$\implies(2y-2x)\dfrac{\mathrm dy}{\mathrm dx}=2y-8x$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y-4x}{y-x}$

On this curve, when $x=2$ we have

$4(2)^2+y^2=48+2(2)y\implies y^2-4y-32=(y-8)(y+4)=0\implies y=8$

(ignoring the negative solution because we don't care about it)

The tangent to this curve at the point $(x,y)$ has slope $\dfrac{\mathrm dy}{\mathrm dx}$ . This tangent line is horizontal when its slope is 0. This happens for

$\dfrac{y-4x}{y-x}=0\implies y-4x=0\implies y=4x$

and when $x=2$ , there is a horizontal tangent line to the curve at the point (2, 8).

5 0

3 years ago

Jorge wrote the equation - 6x+4x = 8. What is the value of x?<br> -4<br> -2<br> 2<br> 4

SVETLANKA909090 [29]

Answer:

The answer to this is A. -4

5 0

3 years ago

Read 2 more answers

If 2 + 2 = 4 then what does 2 + 3 make?

Goryan [66]

If two plus two is four therefore two plus three is in fact five.

5 0

4 years ago

Read 2 more answers

A=144pi^2 ft. Find the radius

Yakvenalex [24]

The radius is 12 because 12^2 equals 144

6 0

3 years ago