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MA_775_DIABLO [31]
2 years ago
15

Need help asap!! analyze the diagram below and answer the question that follows.

Mathematics
1 answer:
katrin2010 [14]2 years ago
5 0

Answer:

D) cos^-1 (f/e)

Step-by-step explanation:

Since you only know two sides, DE = f, and DF = e, you need to use cosine to find the measure of ∠D.

Let x represent m∠D

cos x = f/e

To find x, take the inverse of cos, so:

cos^-1 (f/e) = x

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20+ 5*5 *2=

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dem82 [27]

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What do you mean by that?

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Y=(1/2)^x +2. What is the horizontal asymptote of this function?
professor190 [17]
\lim_{x\to -\infty} \left(\frac{1}{2}\right)^x+2=\infty+2=\infty\\
\lim_{x\to \infty} \left(\frac{1}{2}\right)^x+2=0+2=2\\

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6 0
3 years ago
Assume that f(x)=ln(1+x) is the given function and that Pn represents the nth Taylor Polynomial centered at x=0. Find the least
WINSTONCH [101]

Answer:

the least integer for n is 2

Step-by-step explanation:

We are given;

f(x) = ln(1+x)

centered at x=0

Pn(0.2)

Error < 0.01

We will use the format;

[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01

So;

f(x) = ln(1+x)

First derivative: f'(x) = 1/(x + 1) < 0! = 1

2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1

3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2

4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6

This follows that;

Max|f^(n+1) (c)| < n!

Thus, error is;

(n!/(n + 1)!) × 0.2^(n + 1) < 0.01

This gives;

(1/(n + 1)) × 0.2^(n + 1) < 0.01

Let's try n = 1

(1/(1 + 1)) × 0.2^(1 + 1) = 0.02

This is greater than 0.01 and so it will not work.

Let's try n = 2

(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267

This is less than 0.01.

So,the least integer for n is 2

7 0
3 years ago
The equation of the line with slope −4 that goes through the point (8,−3)
Korolek [52]

Answer:

y = -4x + 29

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-3 = -32+b

29=b

7 0
3 years ago
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