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3 years ago

Helpppppppppppp asap

Mathematics

1 answer:

pishuonlain [190]3 years ago

8 0

6(3x+5)!!!!!!!!!!!!!!!!!!!!!!

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Which quadrant is -150 degrees in?

podryga [215]

The top left and bottom left

5 0

4 years ago

Can some one help quickly. Please show work

jenyasd209 [6]

Answer:50

Step-by-step explanation: you divide 108 by 2 then round 54 to 50 since 4 is not enough to round to 60

3 0

3 years ago

People are arriving at an amusement park at a constant rate if 450people arrive in 15 minutes how many people arrive each minute

klio [65]

To find the answer, you have to divide-
the people arriving/minute

So it would be -
450/15 = 30
There are 30 people arriving each minute.

6 0

4 years ago

A 10.0 kg and a 2.0 kg cart approach each other on a horizontal frictionless air track. Their

Flura [38]

the final speed in m/s of the 10.0 kg is 2.53 m/s .

<u>Step-by-step explanation:</u>

Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:

We know that in an elastic collision :

⇒ Total kinetic energy before collision = Total kinetic energy after collision

⇒ $96 = \frac{1}{2}M_1(v_1)^2 + \frac{1}{2}M_2(v_2)^2$

⇒ $96 = \frac{1}{2}(10)(v_1)^2 + \frac{1}{2}(2)(8)^2$

⇒ $96=5(v_1)^2 + 64$

⇒ $5(v_1)^2 =32$

⇒ $(v_1)^2 =6.4$

⇒ $v_1 =2.53 m/s$

Therefore , the final speed in m/s of the 10.0 kg is 2.53 m/s .

8 0

3 years ago

7. AstudyoftheannualnumberofbreedingpairsofBaldEaglesinMichiganfrom1990-2006,showsthenumberofpairs, E(t), can be represented by

soldier1979 [14.2K]

Well, the give us 1990-2006 as the time period. If you don't know how many years that is and don't feel like counting: 2006-1990=16

Then plug it in the equation t=16
E(t)=204(1.04)t
E(16)=204(1.04)16
E(16)=212.16•16
E(16)=3394.46

6 0

4 years ago