What is the range of y = log, X?

Mathematics

1 answer:

Sindrei [870]3 years ago

8 0

O all real numbers less than 0

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How do I solve this question?

zubka84 [21]

Answer:

$f(x) = \frac{108}{7} (\frac{7}{6})^x$ or $f(x) = 15.429(1.167)^x$

Step-by-step explanation:

No need for a calculator.

Assuming that the equation is in the form $y = ab^x$ , we can plug in points to get our equation. For ease, let's use (1,18) and (2,21). When plugging these points in, we get $18 = ab^1, 21 = ab^2$ . Now let's divide the equations to get rid of $a$ : $\frac{21 = ab^2}{18 = ab^1} = \frac{21}{18} = \frac{7}{6} = b$ . Now that we have $b$ , we can plug in the value we just calculated to solve for $a$ : $18 = a(\frac{7}{6} )^1$ , and solving for $a$ , we get $a = \frac{108}{7}$ .