we know that
The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.
The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.
If the probability that any one egg has 1/6 chance of salmonella
then
the probability that any one egg will not have salmonella = 5/6.
Therefore
for all 5 to not have salmonella
= (5/6)^5 = 3125 / 7776
= 0.401877 = 0.40 to 2 decimal places
REMEMBER this is the probability that NONE have salmonella
Therefore
the probability that at least one does = 1 - 0.40
= 0.60
the answer is
0.60 or 60%
It’s bull Peter C your welcome :)
Answer:
14 more flower would bloom if 21 more tulip bulb is planted.
Step-by-step explanation:
Given ratio for tulip bulbs and flowers is 15:10.
Now, finding number of flower to bloom if 21 tulip bulb are planted.
Assume if 21 tulip bulbs are planted then number of flower would bloom be"x"
ratio given: 
Cross multiplying the ratio to get:
⇒x= 
∴
Hence, 14 flowers would bloom if 21 tulip bulb are planted.
If total tulip bulb is 
, then 
would bloom.
Answer:
59
Step-by-step explanation:
Because multiply 18.8 and 3.14 and get a number with a decimal so round up and get 59 :)
The answer choice for your problem would be b most likely
