Question

The total current of a parallel circuit is 9+j2 amps and the current of one component of the circuit is 3−j5 amps. What is the current of the other component of the circuit?

Answer 1

Apply law of total resistance in parallel circuit

$\\ \tt\hookrightarrow \dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

$\\ \tt\hookrightarrow \dfrac{1}{9+2J}=\dfrac{1}{3-5j}+\dfrac{1}{R_2}$

$\\ \tt\hookrightarrow \dfrac{1}{R_2}=\dfrac{1}{9+2J}-\dfrac{1}{3-5J}$

$\\ \tt\hookrightarrow \dfrac{1}{R_2}=\dfrac{3-5J-9-2J}{(9+2J)(3-5J)}$

$\\ \tt\hookrightarrow R_2=\dfrac{(9+2J)(3-5J)}{-6-7J}$