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Dovator [93]
2 years ago
14

The total current of a parallel circuit is 9+j2 amps and the current of one component of the circuit is 3−j5 amps. What is the c

urrent of the other component of the circuit?
Mathematics
1 answer:
stealth61 [152]2 years ago
4 0

Apply law of total resistance in parallel circuit

\\ \tt\hookrightarrow \dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}

\\ \tt\hookrightarrow \dfrac{1}{9+2J}=\dfrac{1}{3-5j}+\dfrac{1}{R_2}

\\ \tt\hookrightarrow \dfrac{1}{R_2}=\dfrac{1}{9+2J}-\dfrac{1}{3-5J}

\\ \tt\hookrightarrow \dfrac{1}{R_2}=\dfrac{3-5J-9-2J}{(9+2J)(3-5J)}

\\ \tt\hookrightarrow R_2=\dfrac{(9+2J)(3-5J)}{-6-7J}

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