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kupik [55]
2 years ago
9

If f(x) = x2 + 1 and g(x) = x - 4, which value is equivalent to (fog)(10)

Mathematics
1 answer:
aksik [14]2 years ago
8 0
To get this f(g(10))

We do g(x)= 10-4= 6

This plug this into f(6)= 6^2 +1= 37

The answer is 37
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
Solve this system of equations.
Dennis_Churaev [7]

Answer:

<em>x = -3 and y = 0</em>

Step-by-step explanation:

<em>It would be more direct to apply elimination in this problem, rather than substitution:</em>

  2x + 6y = -6       ⇒      2x + 6y = -6       ⇒      10x = - 30

+ 2(4x - 3y = -12)        +  8x - 6y = -24

<em>Now let us solve for x through simply algebra:</em>

10x = -30,

  <em>x = -3</em>

<em>Substitute this value of x into the first equation to get the value of y:</em>

2( -3 ) + 6y = -6,

-6 + 6y = -6,

  6y = 0,

    <em>y = 0</em>

4 0
3 years ago
Read 2 more answers
The polynomial is a difference of perfect squares. Use the formula a2 – b2 = (a + b)(a – b) to factor completely. 81x2 – 49 The
borishaifa [10]
To answer your question: Rewrite <span>81<span>x2</span></span> as <span><span>(<span>9x</span>)</span>2</span>.<span><span><span>(<span>9x</span>)</span>2</span><span>−49</span></span>Rewrite 49 as <span>72</span>.<span><span><span>(<span>9x</span>)</span>2</span><span>−<span>72</span></span></span> Both terms are perfect squares, factor using the difference of squares formula, <span><span><span>a2</span><span>−<span>b2</span></span></span>=<span><span>(<span>a+b</span>)</span><span>(<span>a<span>−b</span></span>)</span></span></span> where <span>a=<span>9x</span></span> and <span>b=7</span>.<span><span>(<span><span>9x</span>+7</span>)</span><span>(<span><span>9x</span><span>−7</span></span><span>)</span></span></span>
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3 years ago
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Greatest common factor 48x^5,39x^6
lora16 [44]
4,853,096 is the number
6 0
4 years ago
Find the equation of the graphed line.
belka [17]
<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\bf \leadsto Hence \ option\ [d]\ \bigg(y =  \dfrac{5}{2}x + 5\bigg) \ is \ correct  }}}

<h3><u>Step-by-step explanation:</u></h3>

Here from the given graph we can see that the graph the graph intersects x axis at (2,0) and y axis at (5,0). On seeing options it's clear that we have to use Slope intercept form . Which is :-

\large\boxed{\orange{\bf y = mx + c} }

We know that slope is \tan\theta. So here slope will be ,

\red{\implies slope = \tan\theta} \\\\\implies slope =\dfrac{PERPENDICULAR}{BASE} \\\\\bf \implies slope =\dfrac{5}{2}

Hence the slope is 5/2 . And here value of c will be 5 since it cuts y axis at (5,0).

\purple{\implies y = mx + c }\\\\\implies y = \dfrac{5}{2}x + 5 \\\\\underline{\boxed{\red{\tt \implies y = \dfrac{5}{2}x + 5 }}}

<h3><u>Hence</u><u> </u><u>option</u><u> </u><u>[</u><u> </u><u>d</u><u> </u><u>]</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u> </u><u>.</u><u> </u></h3>
4 0
3 years ago
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