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kupik [55]
2 years ago
9

If f(x) = x2 + 1 and g(x) = x - 4, which value is equivalent to (fog)(10)

Mathematics
1 answer:
aksik [14]2 years ago
8 0
To get this f(g(10))

We do g(x)= 10-4= 6

This plug this into f(6)= 6^2 +1= 37

The answer is 37
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Answer:

\frac{a}{b + 2}

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PLEASE HELP ASAP!!!!! WILL MARK BRAINLIEST FOR FIRST CORRECT ANSWER!!!!
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4/5 is the answer. 
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The figures below are similar.
Dafna1 [17]

Answer:

  a) 2.5

  b) 6.25

Step-by-step explanation:

For similar figures, the ratio of any corresponding linear dimensions is the same. The ratio of areas is the square of that.

<h3>Application</h3>

The ratio of linear dimensions, larger to smaller, is ...

  (30 yd)/(12 yd) = 2.5

<h3>a) Perimeter</h3>

Perimeter is a linear dimension, the sum of side lengths. The ratio of perimeters is 2.5.

<h3>b) Area</h3>

The ratio of areas, larger to smaller, is the square of the scale factor for side lengths:

  (2.5)² = 6.25

The ratio of the areas of the larger to smaller figure is 6.25.

7 0
2 years ago
I'm stuck and really need help. I can't figure out the rest.
Ad libitum [116K]

Answer:

The next statements are are;

Statement                                                  {}        Reason

Segment \overline {DC} ≅ Segment \overline {AB}                        {}   CPCTC

\overline {AD} ≅ \overline {BC} and \overline {DC} ≅ \overline {AB}, therefore;

ABCD is a parallelogram                    {}               Parallelogram side theorem

Step-by-step explanation:

Statement                                                  {}        Reason

Segment \overline {DC} ≅ Segment \overline {AB}  by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

Given that \overline {AD} ≅ \overline {BC} and we have that \overline {DC} ≅ \overline {AB}, we get;

ABCD is a parallelogram                    {}               Parallelogram side theorem

The parallelogram side theorem states that a quadrilateral is a parallelogram if it has two pairs or sets of congruent opposite sides.

4 0
3 years ago
Any athlete who fails the Enormous State University's women's soccer fitness test is automatically dropped from the team. Last y
castortr0y [4]

Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Fail the test.
  • Event B: Unfit.

The probability of <u>failing the test</u> is composed by:

  • 46% of 37%(are fit).
  • 100% of 63%(not fit).

Hence:

P(A) = 0.46(0.37) + 0.63 = 0.8002

The probability of both failing the test and being unfit is:

P(A \cap B) = 0.63

Hence, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.63}{0.8002} = 0.7873

0.7873 = 78.73% probability that Mona was justifiably dropped.

A similar problem is given at brainly.com/question/14398287

3 0
2 years ago
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