Question

Write 6(x – 5)4 4(x – 5)2 6 = 0 in the form of a quadratic by using substitution. 6u2 4u 6 = 0, where u = x – 5 6u2 4u 6 = 0, where u = (x – 5)2 6u4 4u 6 = 0, where u = x – 5 6u4 4u 6 = 0, where u = (x – 5)2.

Answer 1

A quadratic equation is the equation in which the unknown variable is one and the highest power of the unknown variable is two.

The quadratic form of the given equation is,

$6u\timesu+4u^2+6=0$

Where,

$u=(x-5)^2$

The option 4 is the correct option.

What is quadratic equation?

A quadratic equation is the equation in which the unknown variable is one and the highest power of the unknown variable is two.

The standard form of the quadratic equation is,

$ax^2+bx+c=0$

Here, $a,b,c$ is the real numbers and $x$ is the variable.

Given information-

The given expression in the problem is,

$6(x-5)^4+4(x-5)^2+6=0$

Rewrite the equation as,

$6(x-5)^2\times(x-5)^2+4(x-5)^2+6=0$

Let,

$u=(x-5)^2$

Then the given expression can be written as,

$6u\timesu+4u^2+6=0$

Hence, the quadratic form of the given equation is,

$6u\timesu+4u^2+6=0$

Where,

$u=(x-5)^2$

The option 4 is the correct option.

Learn more about the quadratic equation here;

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