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Igoryamba
3 years ago
6

I need help please. DUE TOMORROW!

Mathematics
2 answers:
Julli [10]3 years ago
5 0
In order to get your final answer to this problem,, you will need to factor out \frac{2}{9} from the expression.
\frac{2}{9}  × (j + 3) 
Since we cannot simplify this expression down any further and we have removed our coefficient,, the correct answer to your question is going to be \frac{2}{9}  × (j + 3).
Let me know if you have any further questions.
:)
amid [387]3 years ago
5 0
You are given (2/9)j + 2/3.  The variable is j and the coefficient of j is (2/9).  <em>If you're supposed to factor out the coeff. of j, factor out (2/9) from both (2.9)j and (2/3):

(2/9)(j + 3) (answer)
</em>
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The author drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed
algol [13]

Answer:

\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860

p_v = P(\chi^2_{5} >5.860)=0.32

Since the p value is higher than the significance level assumed 0.05 we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we can assume that we have equally like results.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Number:      1,    2 ,   3 ,  4 , 5    ,6

Frequency: 27, 31, 42, 40, 28, 32

We need to conduct a chi square test in order to check the following hypothesis:

H0: The outcomes are equally likely.

H1: The outcomes are not equally likely.

The level of significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The observed values are given:

O_{1}=27   O_{2}=31

O_{3}=42  O_{4}=40

O_{5}=28  O_{6}=32

The expected values are given by:

E_{1} =\frac{1}{6}*200=33.33   E_{2} =\frac{1}{6}*200=33.33

E_{3} =\frac{1}{6}*200=33.33   E_{4} =\frac{1}{6}*200=33.33

E_{5} =\frac{1}{6}*200=33.33   E_{6} =\frac{1}{6}*200=33.33

And now we can calculate the statistic:

\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860

Now we can calculate the degrees of freedom for the statistic given by:

df=Categories-1=6-1=5

And we can calculate the p value given by:

p_v = P(\chi^2_{5} >5.860)=0.32

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(5.860,5,TRUE)"

Since the p value is higher than the significance level assumed 0.05 we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we can assume that we have equally like results.

4 0
3 years ago
Find the volume of each figure. Round to the nearest tenth if necessary.​
RideAnS [48]

Answer:

396

Step-by-step explanation:

the volume of a rectangular is calculated as V=l×w×h

l=11, w=12, h=3

V=11×12×3

V= 396

3 0
3 years ago
Please help me due today....
Monica [59]

Answer:

i belive it something with 4 and 6 like 10 or 4/6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Factor the following polynomial completely.<br> -x^2y^2 + x^4 + 9y^2 - 9x^2
castortr0y [4]
See attached picture for answer:

3 0
3 years ago
Will the ball clear the crossbar of the goal post, which is 10 feer off the fround.
Allisa [31]

The problem gives you X, so replace X witht he given vaule and solve for y:


y = -0.1x^2 + 4X

X = 40

y = -0.1(40)^2 +4(40)

y = -0.1(1600) + 160

y = -160 + 160

y = 0


7 0
3 years ago
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