Note: Consider we need to find the vertices of the triangle A'B'C'
Given:
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).
To find:
The vertices of the triangle A'B'C'.
Solution:
If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

Using this rule, we get



Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).
Answer:
62.8
Step-by-step explanation:
20 x П =
20 x 3.14 = 62.8
Answer:
What is the table? what are the values? If you can't insert a picture please type the like f(x)= y
Step-by-step explanation:
Step-by-step explanation:
f(x) = x² − 6x + 9
f(½) = (½)² − 6(½) + 9
f(½) = ¼ − 3 + 9
f(½) = 6¼
The value is 6¼, or as an improper fraction, 25/4.