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just olya [345]
4 years ago
6

Simplify the expression 16^1/2

Mathematics
1 answer:
zlopas [31]4 years ago
5 0

16^{\frac{1}{2} } = \sqrt[2]{16} = 4

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Which circles have an area of 36pift2?
san4es73 [151]
Area=pi times radius^2
area=36pi
36pi=pi times radius^2
divide both sides by pi
36=radius^2
square root both sides
6=radius

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2 times 6=12
radius=6
diamater=12

the answers area A and D
(if you know your radius and diameter, you would know that diameter is 2 times radius and you could eliminate 2 choices imedietly (B and C))
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Which relation is represented by mapping below​
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it is D

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How is adding and subtracting mixed numbers similar to adding and subtracting fractions? How is adding and subtracting mixed num
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4 years ago
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Fantom [35]

-3y = -4x +51

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7 0
3 years ago
Read 2 more answers
4. According to statistics reported on IN-CORP a surprising number of motor vehicles are not covered by insurance. Sample result
son4ous [18]

Answer:

a) 0.23

b) The 95% confidence interval for the population proportion is (0.1717, 0.2883).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Point estimate

The point estimate is:

\pi = \frac{46}{200} = 0.23

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.23 - 1.96\sqrt{\frac{0.23*0.77}{200}} = 0.1717

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.23 + 1.96\sqrt{\frac{0.23*0.77}{200}} = 0.2883

The 95% confidence interval for the population proportion is (0.1717, 0.2883).

5 0
3 years ago
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