Question

If you know that nine to the third power = 729, describe how to find nine to the fourth power without having to multiply four 9s.

Answer 1

Remember
$(x^m)(x^n)=x^{m+n}$

so
$(9^3)(9^1)=9^{3+1}=9^4$
9^3=729
so

$(729)(9)=9^4$
that's how yo do it, muliply 9 by 729