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Llana [10]
2 years ago
7

Question 4 of 25

Mathematics
1 answer:
soldi70 [24.7K]2 years ago
7 0

Answer:

D)graph c

Step-by-step explanation:

it's my opinion do not take it as important

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PLEASE HELP, BRAINLIEST FOR THE BEST ANSWER
Zolol [24]

Answer:

Use the distance formula to determine the distance between the two points.

Distance

=

√(x2−x1)^2 + (y2−y1)^2

Substitute the actual values of the points into the distance formula.

√ ( (−6) − 0)^2 +( (−3) − 4)^2

Subtract 0 from −6

√(−6)^2 + ( ( −3 ) −4 )^2

Raise −6 to the power of 2

√36 + ( ( −3 ) −4 )^2

Subtract 4 from −3

√36 + ( −7 )^2

Raise −7 to the power of 2

√ 36 + 49

Add 36 and 49

√85

5 0
3 years ago
Help Calculus please help
Tamiku [17]
This problem is related to the concept composite function
6 0
4 years ago
What is 145 ÷ 891 + 153 ÷ 141 + 1/1?
ruslelena [56]

Answer: Exact form: 94133 / 41877. Mixed number form: 2 10379 / 41877

Step-by-step explanation: divide 145 and 891. Then add 153. Then divide again 141 and 153. Then add 1/1.

Hope this helps!

7 0
3 years ago
Read 2 more answers
Use the drop-down menus to choose steps in order to correctly solve 4k−6=−2k−16−2 please help just need steps
luda_lava [24]
4k-6=-2k-16-2
4k-6=-2k-18
6k-6=-18
6k=-12
k=-2
3 0
3 years ago
A cold drink is poured out at 52°F. After 2 minutes of sitting in a 72°F room, its temperature has risen to 55°F. Find an equati
I am Lyosha [343]

Answer:

The model for the temperature of the drink can be written as

T=72-20e^{-0.08t}

Step-by-step explanation:

For a cold drink in a hotter room, we can say that the rate of change of temperature of the drink is proportional to the difference of temperature between the drink and the room.

We can model that in this way

\frac{dT}{dt}=k*(T_r-T)

If we rearrange and integrate

\int\frac{dT}{(T-Tr)} =-k*\int dt\\\\ln(T-T_r)=-kt+C1\\\\T-T_r=Ce^{-kt}\\\\T=T_r+Ce^{-kt}

We know that at time 0, the temperature of the drink was 52°F. Then we have:

T=T_r+Ce^{-kt}\\\\52=72+Ce^0=72+C\\\\C=-20

We also know that at t=2, T=55°F

T=T_r+Ce^{-kt}\\\\55=72-20e^{-k*2}\\\\e^{-k*2}=(72-55)/20=0.85\\\\-2k=ln(0.85)=-0.1625\\\\k=0.08

The model for the temperature of the drink can be written as

T=72-20e^{-0.08t}

7 0
4 years ago
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