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andre [41]
4 years ago
11

janice bought her mother a bunch of 10 flowers. two of the flowers are daisies. one half of the remaining flowers are tulips. wr

ite the fraction of the flowers that are daisies
Mathematics
1 answer:
Paul [167]4 years ago
3 0
2/10, or simplified as 1/5.
Since the part that are daisies is 2, and the total number of flowers is 10, the fraction is 2/10 or 1/5.
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Francis is at the state fair. A fair concession stand is selling funnel cakes for $3.50 and deep-fried Oreos for $2.00. Write an
VladimirAG [237]

The equation that models the number of funnel cakes and Oreos he can buy is 3.50x + 2.0y = 42

Data given;

  • Cost of cakes = $3.50
  • Cost of Oreos = $2.00
  • The total amount spent = $42.00
<h3>What is the Equation</h3>

To solve this problem, we just need to write out an equation to show how he can spend $42.00 in the fair on Oreos and Cakes.

Let x represent the cakes

Let y represent the Oreos

The equation is thus;

3.50x + 2.0y = 42.00

The equation that shows the number of Cakes and Oreos can by is

3.50x + 2.0y = 42

Learn more about equation here;

brainly.com/question/13729904

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2 years ago
Evaluate each expression by (1) using the Distributive Property and (2) evaluating inside the parentheses first.
galina1969 [7]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Translate seven less than 6 times a number is 29
abruzzese [7]
6-7n=29 would be your answer
7 0
3 years ago
How do I show my work if these are parallel or not?
JulijaS [17]

You can determine if things are parallel if the lines will eventually meet or not. M and N are one line while P and Q are also a line. Therefore, we can say P is one line while M is also one line. The answer would be is that they are parallel, the two lines will not crash with one another. To show your work as if they are parallel, you can continue the lines down and write a note saying they won't collide or you just say they won't collide and are parallel lines.

6 0
3 years ago
Write y=2x^2+12x+14 In vertex form
ratelena [41]

Answer:

\large\boxed{y=2(x+3)^2-6}

Step-by-step explanation:

The vertex form of a parabola f(x) = ax² + bx + c:

y=a(x-h)^2+k

(h, k) - vertex

h=\dfrac{-b}{2a}\\\\k=f(h)

We have the equation:

y=2x^2+12x+14\\\\a=2,\ b=12,\ c=14\\\\h=\dfrac{-12}{2(2)}=\dfrac{-12}{4}=-3\\\\k=f(-3)=2(-3)^2+12(-3)+12=2(9)-36+12=18-36+12=-6

Finally:

y=2(x-(-3))^2+(-6)=2(x+3)^2-6

7 0
4 years ago
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