Answer: ∠A = 70°
because ABC is an isosceles triangle and AB = AC
=> ∠B = ∠C = 55°
=> ∠A = 180-(∠B + ∠C) = 180° - 55°.2 = 70°
Step-by-step explanation:
We know that
<span>each space on the balance represents
1 kg/ 10 spaces----------> 0.10 kg
in the picture there are 14 spaces
so
14*0.1-------> 1.4 Kg
</span>
Part A) About how many kilograms of oranges does Andrea have? Round your answer to the nearest kilogram
Andrea has 1.4 kg of oranges------> to the nearest kilogram-----> 1 Kg
the answer is
1 kg
Part B) About how many more kilograms of oranges does Andrea need?
Andrea needs=(4 Kg-1.4 Kg)------> 2.6 Kg
the answer part B) is
2.6 Kg
The equation formula of the circle is (x-h)^2 + (y-k)^2 = r^2
where (h,k) the point of the center of the circle
and (r) is the radius of the circle
so if the center of the circle = (-2,-4)
by subs. in the formula we get (x-(-2))^2 + (y-(-4))^2 = r^2
then the equation will be (x+2)^2 + (y+4)^2 = r^2
now we want to define the radius of the circle r
since point (3,8) lay on the circle so we can
then subs. in the equation to get the radius
(x+2)^2 +(y+4)^2 = r^2
(3+2)^2 +(8+4)^2 = r^2
25 + 144 = r^2
r^2 = 169
r= 13
the radius of the circle is 13
so by subs in the equation we get
(x+2)^2 + (y+4)^2 = 169
so it is the first answer in the choices
The correct answer is 50%.
Approximately the middle 50% of data is contained inside the box of a box plot.
Answer:
0.3334 ft
Step-by-step explanation:
Measure the height and radius of the tank. The radius is the distance from the center of the tank to its outer edge. Another way to find the radius is to divide the diameter, or width, by two. Square the radius by multiplying the radius times itself and then multiply it by 3.1416, which is the constant pi.
- Given height and volume: r = √(V / (π * h)),
- Given height and lateral area: r = A_l / (2 * π * h),
- Given height and total area: r = (√(h² + 2 * A / π) - h) / 2,
- Given height and diagonal: r = √(h² + d²) / 2,
- Given height and surface-area-to-volume ratio: r = 2 * h / (h * SA:V - 2),
- Given volume and lateral area: r = 2 * V / A_l,
- Given base area: r = √(A_b / (2 * π)),
- Given lateral area and total area: r = √((A - A_l) / (2 * π)).
