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Andru [333]
3 years ago
7

A little help? A set of numbers is given below. √72, 9.25, √83, 2, 8.7 Which list correctly orders the numbers from least to gre

atest?​
Mathematics
1 answer:
myrzilka [38]3 years ago
6 0

Answer:

9.25, 83^1/2, 8.7, 72^1/2, 2 From greatest to least

2, 72^1/2, 8.7, 83^1/2, 9.25 from least to greatest

Step-by-step explanation:

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The State Board of Education has $2,183 to buy new calculators. If each calculator costs $37, how many calculators can the board
Tema [17]

Answer:

59

Step-by-step explanation:

They could buy 59

You solve this by dividing the total amount of money ($2183) by the other amount ($37) which is 59

5 0
3 years ago
The heights of 20-year-old females are normally distributed with a mean of 64 inches and a standard deviation of 2 inches. What
natali 33 [55]

Answer: z= -1

Step-by-step explanation: z= (62-64)/2 = -1

5 0
3 years ago
Read 2 more answers
Can someone help me with this please?
AVprozaik [17]

Answer:

y=70°

z= 60°

w= 70°

Step-by-step explanation:

Since the two triangles are similar, we know that all of the corresponding angles must be the same.  On the triangle on the left, we can see that the angle formed between sides AB and AC is 60°.  This means that the same angle is formed at Z, which is in the same location on the triangle to the right.  From there, we can find the missing angle, W, from the difference of 180°.

180°-50°-60°=70°.

The same way we found Z, we can also find Y, since it has to be the same as W.

8 0
2 years ago
Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14∣ < ε. (Find the largest
s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and \varepsilon>0, we want to find a \delta such that |f(x)-14|

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that |x-5|. Then

|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta.

Then, if |x-5|, then |f(x)-14|. So, in this case, if 3\delta \leq \varepsilon we get that |f(x)-14|. The maximum value of delta is \frac{\varepsilon}{3}.

By definition, this procedure proves that \lim_{x\to 5}f(x) = 14. Note that f(5)=14, so this proves that f is continous at x=5.

3 0
3 years ago
Rectangle a has area 40 cm square and length 8 cm. the area of rectangle b is one half the area of rectangle
lesya [120]
Area of rectangle b=1/2 area of rectangle a=40/2=20 cm²
Length=8 cm 
Width of rectangle b=20/8 =2.5 cm
5 0
3 years ago
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