Write an exponential model given the two points (10,130) and (11,240).
1 answer:
Answer:
y = 130(24/13)^(x -10)
Step-by-step explanation:
The y-value changes by a factor of 240/130 = 24/13 for a unit change in the x-value. This means we can write the function as though it had an initial value of 130 and a growth factor of 24/13, translated 10 units to the right.
y = 130(24/13)^(x -10)
_____
<em>Additional comment</em>
This can also be written in the form ...
y = a·e^(kx)
where a=130·(24/13)^(-10) ≈ 0.28266, and k=ln(24/13) ≈ 0.61310
You might be interested in
We know that
<span>foci on x-axis-------> is a ellipse with horizontal major axis
the equation is
(x</span>²/a²)+(y²/b²)=1
major axis is th<span>e </span>x<span>-axis with length </span><span>2<span>a
2a=14--------> a=7
</span></span>minor axis is the y<span>-axis with length </span><span>2<span>b
2b=4-----> b=2
the equation is
</span></span>(x²/a²)+(y²/b²)=1------> (x²/7²)+(y²/2²)=1-----> (x²/49)+(y²/4)=1
the answer is
(x²/49)+(y²/4)=1
see the attached figure
<span>foci on x-axis-------> is a ellipse with horizontal major axis
the equation is
(x</span>²/a²)+(y²/b²)=1
major axis is th<span>e </span>x<span>-axis with length </span><span>2<span>a
2a=14--------> a=7
</span></span>minor axis is the y<span>-axis with length </span><span>2<span>b
2b=4-----> b=2
the equation is
</span></span>(x²/a²)+(y²/b²)=1------> (x²/7²)+(y²/2²)=1-----> (x²/49)+(y²/4)=1
the answer is
(x²/49)+(y²/4)=1
see the attached figure