Please Answer !which of the following equation of a line parallel to the line y=3x+2, passing through the point (10,1)?

1, 1/2, 1/4, 1/8, ... What's the pattern rule and the next three numbers? Please someone help me!

mel-nik [20]

Answer:

1/16

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Sophie has 7 cookies she wants to share equally with ten friends at her party. Part A If she separates all of the cookies and gi

STatiana [176]

Answer:

Each friend gets 0.7 cookie

8 cookies

Step-by-step explanation:

A.

Number of cookies = 7

Number of friends = 10

how much cookie will each friend receive?

Number of cookie each friend get = number of cookies / number of friends

= 7/10

= 0.7 cookie

Each friend gets 0.7 cookie

B.

If each friend 1 1/2 cookies

how many more cookies would she need?

Total number of cookies needed = 1 1/2 × 10

= 3/2 × 10

= 30/2

= 15 cookies

She already has 7 cookies

Number of cookies needed more = 15 cookies - 7 cookies

= 8 cookies

7 0

3 years ago

Cos 0=9/15 find tan 0

Liula [17]

Answer:

I HAVE NO CLUE BUT HAVE A NICE DAY....

5 0

3 years ago

On a rectangular hyperbola, if one point is (2, 3) and y varies inversely to x, find y when x is 6.

pickupchik [31]

Answer:

y = 1

Step-by-step explanation:

y is inversely proportion to x means that ,

y ∝ 1/x or ,

$y\ \alpha\ \frac{1}{x}$

When we remove the proportionality sign we get,

$y=k(\frac{1}{x})\\y=\frac{k}{x} \\$

now we know the point is (2 , 3) which means it corresponds to (x , y) which furthermore means y=3 when x=2,

so we insert these values and get the value of k.

$y=\frac{k}{x} \\\\3=\frac{k}{2}\\\\6=k\\$

now the equation becomes,

$y=\frac{6}{x}$

now we need to find y when x is 6 so just replace x with 6

$y=\frac{6}{x}\\\\y=\frac{6}{6} \\\\y=1$

so we get the value of y is 1

6 0

3 years ago

The average density of the material in intergalactic space is approximately 2.5 × 10–27 kg/m3. what is the volume of a lead samp

Lesechka [4]

Answer:

e. $1.8\times 10^{-6}m^3$

Step-by-step explanation:

It is given that,

The density of intergalactic space material is $2.5 \times 10^{-27}$ kg per cubic meter.

And the volume of intergalactic space material is $8.0\times 10^{24} m^3$

So the mass of that much intergalactic space material is,

$m= \rho\times v$ , where 'm' is the mass, and 'v' is the volume.

Putting the values we get,

$m=2.5 \times 10^{-27}\times 8.0 \times 10^{24}$

$m=20\times 10^{(-27+24)}=20\times 10^{-3} kg$

It is also given that the mass of lead is the same as the mass of the intergalactic space material. Therefore, the mass of lead is $20 \times 10^{-3}=2 \times 10^{-2}kg$

So the volume of lead is,

$v=\frac{m}{\rho} =\frac{2 \times 10^{-2}}{11300} = 0.00000177 m^3$

$v=1.77 \times 10^{-6}=1.8\times 10^{-6}m^3$

So the volume of lead is $v=1.8\times 10^{-6}m^3$ .

3 0

4 years ago